Php 使用动态地址和动态文件创建zip文件并获取zip文件链接

我想把两个文件，一个是thanks.txt，另一个是file.dat，放入一个带有以下代码的压缩文件中，然后链接到这个压缩文件，但我的代码不能正常运行，我需要帮助来纠正和优化这个代码.

在thanks.txt文件内，客户的用户邮箱中包含以下文本:

Hi, Dear '.$email_address.' Thanks for using it!个

My codes:个

funtion create_zip_file() {
    
    // Get Current User Email Address!
    $current_user = wp_get_current_user();
    $email_address = $current_user->user_email;
    
    $md5_address = md5($email_address);

    $directory_path = 'myfiles/cloud/' . $md5_address . '/';
    if (!file_exists($directory_path)) {
        mkdir($directory_path, 0777, true);
    }
    
    $Myfile = file_put_contents($directory_path . 'file.dat' , $email_address);

    if (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] != 'off') {
        $website_url = 'https://' . $_SERVER['HTTP_HOST'] .'/';
    } else {
        $website_url = 'http://' . $_SERVER['HTTP_HOST'] .'/';
    }

    $result = $website_url . $directory_path . 'file.dat'; 

    $zip = new ZipArchive;
    if ($zip->open($zip_file , ZipArchive::CREATE) === TRUE)
    {
        // Add files to the zip file
        $zip->addFile($result);
        
        // Add a file new.txt file to zip using the text specified
        $zip->addFromString('thanks.txt', 'Hi, Dear '.$email_address.' Thanks for use it!');
     
        // All files are added, so close the zip file
        $zip->close();
        
        // Delete file after zip it
        unlink($result);
    }
    
    $zip_file = $website_url . $directory_path . 'file.zip';
    
    if (file_exists($zip_file)) {
        return $zip_file;
    } else {
        return false;
    }
}

And I call the zip file by the following line:个

<a href="<?php echo create_zip_file();"> Download zip file </a>个

如果我在以下行($zip_file)中使用静态地址:

if ($zip->open($zip_file , ZipArchive::CREATE) === TRUE)个

将创建压缩文件，但当我使用动态地址时，不会创建任何压缩文件