Node.js 使用NodeJS输出检索Base64图像的网络报废

所以L一直在try 使用Node Js进行网络剪贴，我试图刮掉耐克的网站，L设法检索了所有的数据，但图像都是Base64格式的.

以下是耐克网站上的 Select :

<img alt="Nike Air Max Dn Men's Shoes" class="product-card__hero-image css-1fxh5tw" height="100%" loading="eager" sizes="" src="https://static.nike.com/a/images/c_limit,w_592,f_auto/t_product_v1/f50070d2-77a3-4213-aebf-9371d9759548/air-max-dn-shoes-q51Wwn.png" width="100%">

以下是输出: [ 擦破的鞋子: { 名字:‘Nike Air Max Dn’， 售价:210美元， colored颜色 :"男鞋"， 图像:‘数据:图像/gif；base 64，R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7’， HREF:‘https://www.nike.com/ca/t/air-max-dn-shoes-q51Wwn/DV3337-008’ }, {

](https://i.stack.imgur.com/xGWYy.png)

以下是我和Ltry 更改 Select 器的代码，似乎都不起作用:

async function scrapeShoes(url) {
  try {
    const response = await axios.get(url);
    if (response.status === 200) {
      const html = response.data;
      const $ = cheerio.load(html);
      const shoes = [];

      $('.product-card').each((index, element) => {
        const name = $(element).find('.product-card__title').text().trim();
        const price = $(element).find('.product-price').text().trim();
        const color = $(element).find('.product-card__subtitle').text().trim();
        let image = $(element).find('.product-card__hero-image').attr('src');
        const href = $(element).find('.product-card__link-overlay').attr('href');

      
        const shoe = { name, price, color, image, href };
        shoes.push(shoe);
      });

      console.log('Scraped Shoes:', shoes); 
      return shoes;
    } else {
      throw new Error(`Failed to retrieve data. Status code: ${response.status}`);
    }
  } catch (error) {
    throw new Error('Error fetching data:', error);
  }
}

const targetUrl = 'https://www.nike.com/ca/w/new-shoes-3n82yzy7ok';
scrapeShoes(targetUrl)
  .then(() => {

  })
  .catch(error => {
    console.error('Error scraping website:', error);
  });