Node.js MongoDB 根据使用聚合的条件从嵌套数组中删除对象

您需要使用Double $map运算符来迭代数组数组，并使用$cond和$$REMOVE来有条件地删除值:

db.collection.aggregate([
    {
        $addFields: {
            products: {
                $map: {
                    input: "$products",
                    as: "p",
                    in: {
                        title: "$$p.title",
                        phone: {
                            $map: {
                                input: "$$p.phone",
                                in: {
                                    title: "$$this.title",
                                    freePreview: "$$this.freePreview",
                                    video: {
                                        $cond: {
                                            if: {
                                                $eq: [
                                                    false,
                                                    "$$this.freePreview"
                                                ]
                                            },
                                            then: "$$REMOVE",
                                            else: "$$this.video"
                                        }
                                    }
                                }
                            }
                        }
                    }
                }
            }
        }
    }
])

Mongo Playground个

Here's个类似的例子.