我有以下文件(test.txt),我想按如下方式更改其逻辑:
0 becomes 1
1 becomes 2
2 becomes 3
3 becomes 4
4 becomes 5
5 becomes 6
6 becomes 7
7 becomes 8
8 becomes 9
9 becomes 0
$ cat test.txt
69|1074330570|1,sip:+121345633210x3Bverstat=TN-Validation-Passed|tel:+12134565534|0
69|1077822111|2,;tel:+12223120011~sip:+12223120051@vzpps.com;|sip:+13123120022@vzpps.com|0
我想更改最后4位数字,但当x紧邻0x时,0不算数. 例如: 在第一行‘+121345633210x’中,最后4行是3321. 在第二行,‘+12223120011’,最后4个是0011和‘+12223120051’,最后4个是0051 输出应如下所示:
69|1074330570|1,sip:+121345644320x3Bverstat=TN-Validation-Passed|tel:+12134566645|0
69|1077822111|2,;tel:+12223121122~sip:+12223121162@vzpps.com;|sip:+13123121133@vzpps.com|0
它需要排除‘+1’,然后计算‘10’位,我想要替换第三列和第四列中的最后4位.
121345633210 becomes 121345644320 / 12134565534 becomes 12134566645
12223120011 becomes 12223121122 / 12223120051 becomes 12223121162 / 13123120022 becomes 13123121133
当列只是一个数字时,我使用了下面的逻辑.但在这种情况下,它有其他东西,所以下面的逻辑不起作用,但通过添加1位数字来转换数字是正确的.
awk -F"|" -v OFS="|" '
NR>0 {
for (i=3;i<=4;i++) {
str = substr($i, 1, length($i) - 4)
for (j = length($i) - 3; j <= length($i); j++) {
str = str (substr($i, j, 1) + 1) % 10
}
$i = str
}
}
1'