我需要的是将一个变量的值动态地(在循环中)增加另一个变量.以下是我的代码:

while read  Plate City Town Village Area Population; do
    echo "$Plate $City $Town $Village $Area $Population"
    
     printf "\n$totalNumberOfTowns\n " 
     totalNumberOfTowns=$totalNumberOfTowns+$Town
     totalNumberOfVillages=$totalNumberOfVillages+$Village

done < "cities.txt"

what I get when I run my code is a little bit not-correct.

我不明白为什么$totalNumberOfTown变量中有"City".另一个有趣的部分是它还进行计算(它对第三个参数求和，即该市的城镇数量.对于Adana是15，对于Adiyaman是9，以此类推.)

Edit:

Cities.txt的第一行是:

板城镇村区人口

see screenshot:

Edit-2: # I have tried these different syntaxes:

let "totalNumberOfTowns+=$Town" #1 I tried these different syntaxes
totalNumberOfTowns=$((expr $totalNumberOfTowns + $Town)) #2
totalNumberOfTowns=$((totalNumberOfTowns + Town)) #3

然而，他们每个人都给了我一些错误.

以下是示例cities.txt和示例代码:

板城镇村区人口 1 ADANA 15 508 14030 2258718 2 ADIYAMAN 9 420 7614 632459 3 AFYONKARAHİSAR 18 395 14230 736912 4 AĞRI 8 566 11376 535435 5 AMASYA 7 352 5520 335494 6 ANKARA 25 711 25706 5663322 7 ANTALYA 19 545 20723 2548308 34 İSTANBUL 40 166 5196 15462452

code个

#!/usr/bin/env bash

average=0
numberOfCities=80

declare -i totalNumberOfTowns=0 totalNumberOfVillages=0
arrayWithOut=""

while read  Plate City Town Village Area Population; do
    echo "$Plate $City $Town $Village $Area $Population"

    printf "\n$totalNumberOfTowns\n " 
      totalNumberOfTowns+=$Town
     totalNumberOfVillages+=$Village

done < "cities.txt"