Linux 编译过度对齐的动态分配变量时出现 icpc 错误

我试图编译一个C++代码，使用过对齐的变量.如果我try 编译以下代码(MWE)

#include <new>
#include <iostream>

int main()
{
    alignas(32) double *r = new (std::align_val_t{32}) double[3];
    std::cout << "alignof(r) is " << alignof(r) << '\n';
    return 0;
}

如果我使用icpx或g++(在所有情况下，标志-std=c++17都被赋予编译器)，那么一切都会顺利运行.然而，在使用英特尔icpc编译时，我遇到了以下错误

mwe.cpp(6): error: no instance of overloaded "operator new[]" matches the argument list
            argument types are: (unsigned long, std::align_val_t)
      alignas(32) double *r = new (std::align_val_t{32}) double[3];
                              ^
/usr/include/c++/9/new(175): note: this candidate was rejected because arguments do not match
  _GLIBCXX_NODISCARD inline void* operator new[](std::size_t, void* __p) _GLIBCXX_USE_NOEXCEPT
                                  ^
/usr/include/c++/9/new(141): note: this candidate was rejected because arguments do not match
  _GLIBCXX_NODISCARD void* operator new[](std::size_t, const std::nothrow_t&) _GLIBCXX_USE_NOEXCEPT
                           ^
/usr/include/c++/9/new(127): note: this candidate was rejected because mismatch in count of arguments
  _GLIBCXX_NODISCARD void* operator new[](std::size_t) _GLIBCXX_THROW (std::bad_alloc)
                           ^

mwe.cpp(7): warning #3464: the standard "alignof" operator does not accept an expression argument (use a type instead)
      std::cout << "alignof(r) is " << alignof(r) << '\n';
                                              ^

compilation aborted for mwe.cpp (code 2)

我不明白错误是什么.