Kotlin中数据类的equals方法

发布于05月30日

I have the following data class

data class PuzzleBoard(val board: IntArray) {
    val dimension by lazy { Math.sqrt(board.size.toDouble()).toInt() }
}

我读到Kotlin中的数据类GET equals()/hashcode()方法是免费的.

I instantiated two objects.

val board1 = PuzzleBoard(intArrayOf(1,2,3,4,5,6,7,8,0))
val board2 = PuzzleBoard(intArrayOf(1,2,3,4,5,6,7,8,0))

但是，下面的语句仍然返回FALSE.

board1 == board2
board1.equals(board2)

推荐答案

在Kotlin data类等式判断中，数组和其他类一样，使用equals(...)进行比较，equals(...)比较数组引用，而不是内容.这种行为被描述为here:

So, whenever you say

arr1 == arr2个

DataClass(arr1) == DataClass(arr2)

...

you get the arrays compared through equals(), i.e. referentially.

Given that,

val arr1 = intArrayOf(1, 2, 3)
val arr2 = intArrayOf(1, 2, 3)

println(arr1 == arr2) // false is expected here
println(PuzzleBoard(arr1) == PuzzleBoard(arr2)) // false too

To override this and have the arrays compared structurally, you can implement equals(...)+hashCode() in your data class using Arrays.equals(...) and Arrays.hashCode(...):

override fun equals(other: Any?): Boolean{
    if (this === other) return true
    if (other?.javaClass != javaClass) return false

    other as PuzzleBoard

    if (!Arrays.equals(board, other.board)) return false

    return true
}

override fun hashCode(): Int{
    return Arrays.hashCode(board)
}

^{这段代码是IntelliJ IDEA为非数据类自动生成的代码}

Another solution is to use List<Int> instead of IntArray. Lists are compared structurally, so that you won't need to override anything.