The most straightforward approach I can think of is to just treat the structure as a Map
(of Map
).
对于Gson,这相对容易做到,只要Map
struct 是静态已知的,根的每个分支都有相同的深度,所有的东西都是String
.
import java.io.FileReader;
import java.lang.reflect.Type;
import java.util.Map;
import com.google.gson.Gson;
import com.google.gson.reflect.TypeToken;
public class GsonFoo
{
public static void main(String[] args) throws Exception
{
Gson gson = new Gson();
Type mapType = new TypeToken<Map<String,Map<String, String>>>() {}.getType();
Map<String,Map<String, String>> map = gson.fromJson(new FileReader("input.json"), mapType);
System.out.println(map);
// Get the count...
int count = Integer.parseInt(map.get("0").get("count"));
// Get each numbered entry...
for (int i = 1; i <= count; i++)
{
System.out.println("Entry " + i + ":");
Map<String, String> numberedEntry = map.get(String.valueOf(i));
for (String key : numberedEntry.keySet())
System.out.printf("key=%s, value=%s\n", key, numberedEntry.get(key));
}
// Get the routes...
Map<String, String> routes = map.get("routes");
// Get each route...
System.out.println("Routes:");
for (String key : routes.keySet())
System.out.printf("key=%s, value=%s\n", key, routes.get(key));
}
}
For more dynamic Map
structure handling, I strongly suggest switching to use Jackson, instead of Gson, as Jackson will deserialize any JSON object of any arbitrary complexity into a Java Map
, with just one simple line of code, and it will automatically retain the types of primitive values.
import java.io.File;
import java.util.Map;
import org.codehaus.jackson.map.ObjectMapper;
public class JacksonFoo
{
public static void main(String[] args) throws Exception
{
ObjectMapper mapper = new ObjectMapper();
Map map = mapper.readValue(new File("input.json"), Map.class);
System.out.println(map);
}
}
The same can be achieved with Gson, but it requires dozens of lines of code. (Plus, Gson has other shortcomings that make switching to Jackson well worth it.)