如何自定义将 JAXB 对象列表序列化为 JSON

我正在使用Jersey为服务器组件创建REST web服务.

我想在列表中序列化的JAXB注释对象如下所示:

@XmlRootElement(name = "distribution")
@XmlType(name = "tDistribution", propOrder = {
    "id", "name"
})
public class XMLDistribution {
    private String id;
    private String name;
    // no-args constructor, getters, setters, etc
}

I have a REST resource to retrieve one distribution which looks like this:

@Path("/distribution/{id: [1-9][0-9]*}")
public class RESTDistribution {
    @GET
    @Produces("application/json")
    public XMLDistribution retrieve(@PathParam("id") String id) {
        return retrieveDistribution(Long.parseLong(id));
    }
    // business logic (retrieveDistribution(long))
}

我还有一个REST资源来检索所有发行版的列表，如下所示:

@Path("/distributions")
public class RESTDistributions {
    @GET
    @Produces("application/json")
    public List<XMLDistribution> retrieveAll() {
        return retrieveDistributions();
    }
    // business logic (retrieveDistributions())
}

I use a ContextResolver to customize JAXB serialization, which is currently configured like this:

@Provider
@Produces("application/json")
public class JAXBJSONContextResolver implements ContextResolver<JAXBContext> {
    private JAXBContext context;
    public JAXBJSONContextResolver() throws Exception {
        JSONConfiguration.MappedBuilder b = JSONConfiguration.mapped();
        b.nonStrings("id");
        b.rootUnwrapping(true);
        b.arrays("distribution");
        context = new JSONJAXBContext(b.build(), XMLDistribution.class);
    }
    @Override
    public JAXBContext getContext(Class<?> objectType) {
        return context;
    }
}

Both REST resources work, as well as the context resolver. This is an example of output for the first one:

// path: /distribution/1
{
  "id": 1,
  "name": "Example Distribution"
}

这正是我想要的.以下是列表的输出示例:

// path: /distributions
{
  "distribution": [{
    "id": 1,
    "name": "Sample Distribution 1"
  }, {
    "id": 2,
    "name": "Sample Distribution 2"
  }]
}

Which is not quite what I want.

我不明白为什么里面有一个distribution号标签.我想在上下文解析器中用.rootUnwrapping(true)删除它，但显然这只会删除另一个封闭标记.这是.rootUnwrapping(false)的输出:

// path: /distribution/1
{
  "distribution": {
    "id": 1,
    "name": "Example Distribution"
  }
} // not ok
// path: /distributions
{
  "xMLDistributions": {
    "distribution": [{
      "id": 1,
      "name": "Sample Distribution 1"
    }, {
      "id": 2,
      "name": "Sample Distribution 2"
    }]
  }
}

我还必须配置.arrays("distribution")以始终获得JSON数组，即使只有一个元素.

Ideally, I'd like to have this as an output:

// path: /distribution/1
{
  "id": 1,
  "name": "Example Distribution"
} // currently works
// path: /distributions
[{
  "id": 1,
  "name": "Sample Distribution 1"
}, {
  "id": 2,
  "name": "Sample Distribution 2"
}]

我试图返回一个List<XMLDistribution>、一个XMLDistributionList(围绕列表的包装)、一个XMLDistribution[]，但我找不到一种方法以我所需的格式获得一个简单的JSON发行版array.

我还try 了由JSONConfiguration.natural()、JSONConfiguration.mappedJettison()等返回的其他表示法，但无法得到与我需要的类似的任何表示法.

有人知道是否可以将JAXB配置为这样做吗？