我正在使用jQuery发出Ajax请求.无论HTTP状态代码是400错误还是500错误，我都想执行不同的操作.我怎样才能做到这一点呢？
$.ajax({
type: 'POST',
url: '/controller/action',
data: $form.serialize(),
success: function(data){
alert('horray! 200 status code!');
},
error: function(data){
//get the status code
if (code == 400) {
alert('400 status code! user error');
}
if (code == 500) {
alert('500 status code! server error');
}
},
});
Update:
@GeorgeCummins mentioned that it "seemed odd" to work with the response body. This is the first time that I've attempted doing this sort of thing. Is my approach not a best-practice? What would you recommend? I created another StackOverflow question for this here: What response/status code should I send to an AJAX request when there is a user/form validation error?