Jquery 如何访问 JSON 对象名称值

发布于06月05日

function (data) {
    //add values based on activity type
    //data = JSON.parse(data);
    //alert(abc.Phone1);

    alert(data.myName)

    alert(data.toString());
    if (activityType == "Phone") {
    }
    return;

},

As you can see this callback function of $.ajax taking JSON data from controller.

For example:

[{"name":"myName" ,"address": "myAddress" }]个

在这种情况下，我的第一个alert 给我未定义，第二个/第三个alert 弹出窗口显示:

[{"name":"myName" ,"address": "myAddress" }]个

How can I access value by name so that my first alert filled out with myName which is value of name?

推荐答案

除了解析JSON之外，您还可以执行如下操作:

$.ajax({
  ..
  dataType: 'json' // using json, jquery will make parse for  you
});

要访问JSON的属性，请执行以下操作:

data[0].name;

data[0].address;

Why you need data[0] because data is an array, so to its content retrieve you need data[0] (first element), which gives you an object {"name":"myName" ,"address": "myAddress" }.

And to access property of an object rule is: