JavaScript 等效于 PHP 的 in_array()

不，它没有.出于这个原因，大多数流行的库在其实用程序包中都附带了一个.有关示例，请查看jQuery的100和Prototype的101.

jQuery的实现和您可能想象的一样简单:

function inArray(needle, haystack) {
    var length = haystack.length;
    for(var i = 0; i < length; i++) {
        if(haystack[i] == needle) return true;
    }
    return false;
}

如果你正在处理大量的数组元素，上述方法会很好地解决这个问题.

EDIT:哎呀.我甚至没注意到你想看看一个数组是否在另一个数组中.根据PHP文档，这是PHP in_array的预期行为:

$a = array(array('p', 'h'), array('p', 'r'), 'o');

if (in_array(array('p', 'h'), $a)) {
    echo "'ph' was found\n";
}

if (in_array(array('f', 'i'), $a)) {
    echo "'fi' was found\n";
}

if (in_array('o', $a)) {
    echo "'o' was found\n";
}

// Output:
//  'ph' was found
//  'o' was found

Chris和Alex发布的代码不遵循这种行为.Alex的是Prototype的indexOf的官方版本，Chris的更像PHP的array_intersect.这就是你想要的:

function arrayCompare(a1, a2) {
    if (a1.length != a2.length) return false;
    var length = a2.length;
    for (var i = 0; i < length; i++) {
        if (a1[i] !== a2[i]) return false;
    }
    return true;
}

function inArray(needle, haystack) {
    var length = haystack.length;
    for(var i = 0; i < length; i++) {
        if(typeof haystack[i] == 'object') {
            if(arrayCompare(haystack[i], needle)) return true;
        } else {
            if(haystack[i] == needle) return true;
        }
    }
    return false;
}

这是我对上面内容的测试:

var a = [['p','h'],['p','r'],'o'];
if(inArray(['p','h'], a)) {
    alert('ph was found');
}
if(inArray(['f','i'], a)) {
    alert('fi was found');
}
if(inArray('o', a)) {
    alert('o was found');
}  
// Results:
//   alerts 'ph' was found
//   alerts 'o' was found

请注意，我故意没有扩展数组原型，因为这样做通常是个坏主意.