Javascript 在两个数组范围中输入日期范围

更新countDaysInRange功能的代码

function countDaysInRange(startDate, endDate) {
  var daysInRange1 = isDateInRanges(startDate, rangesInputRange1) ? Math.min(countDays(startDate, endDate, rangesInputRange1), 0) : 0;
  var daysInRange2 = isDateInRanges(startDate, rangesInputRange2) ? Math.min(countDays(startDate, endDate, rangesInputRange2), 0) : 0;

  return daysInRange1 + daysInRange2;
}

function countDays(startDate, endDate, ranges) {
  return ranges.reduce(function (totalDays, range) {
    var overlapStartDate = startDate < range.endDate ? startDate : range.startDate;
    var overlapEndDate = endDate < range.endDate ? endDate : range.endDate;

    if (overlapStartDate <= overlapEndDate) {
      return totalDays + Math.round((overlapEndDate - overlapStartDate) / (1000 * 60 * 60 * 24));
    }
    return totalDays;
  }, 0);
}

现在，countDaysInRange函数分别计算这两个范围内的天数，并返回为重叠或范围内期间计算的总天数.

Update个

Updated Code个

我希望这能有所帮助.

jQuery('#start-date, #end-date').on('change', function() {
  var startDate = parseDate(jQuery('#start-date').val());
  var endDate = parseDate(jQuery('#end-date').val());

  var daysInRange1 = isDateInRanges(startDate, rangesInputRange1) ? countDaysInRange(startDate, endDate, rangesInputRange1) : 0;
  var daysInRange2 = isDateInRanges(startDate, rangesInputRange2) ? countDaysInRange(startDate, endDate, rangesInputRange2) : 0;

  var inputNumber1 = jQuery('input.number1');
  var inputNumber2 = jQuery('input.number2');

  inputNumber1.val(daysInRange1).trigger('change');
  inputNumber2.val(daysInRange2).trigger('change');
});

// Separate countDaysInRange for each range
function countDaysInRange(startDate, endDate, ranges) {
  return ranges.reduce(function(totalDays, range) {
    var overlapStartDate = startDate < range.endDate ? startDate : range.startDate;
    var overlapEndDate = endDate < range.endDate ? endDate : range.endDate;

    if (overlapStartDate <= overlapEndDate) {
      return totalDays + Math.round((overlapEndDate - overlapStartDate) / (1000 * 60 * 60 * 24));
    }
    return totalDays;
  }, 0);
}