Javascript 使用多个相同属性对数组进行筛选

const foodsList=[{foodOrigin:"Padang",foodName:"Gulai",originCode:"PDN"},{foodOrigin:"Padang",foodName:"Rendang",originCode:"PDN"},{foodOrigin:"Palembang",foodName:"Pempek",originCode:"PLG"},{foodOrigin:"Palembang",foodName:"Tekwan",originCode:"PLG"},{foodOrigin:"Yogyakarta",foodName:"Gudeg",originCode:"YKT"}];

const map = new Map;
for (let i = 0; i < foodsList.length; i++) {
    const item = foodsList[i];
    map.has(item.originCode) || map.set(item.originCode, item.foodOrigin);
}

const result = Array.from(map, ([originCode, foodOrigin]) => ({ foodOrigin, originCode }));

console.log(result);

<script benchmark data-count="1">

    const chunk = [{ foodOrigin: "Padang", foodName: "Gulai", originCode: "PDN" }, { foodOrigin: "Padang", foodName: "Rendang", originCode: "PDN" }, { foodOrigin: "Palembang", foodName: "Pempek", originCode: "PLG" }, { foodOrigin: "Palembang", foodName: "Tekwan", originCode: "PLG" }, { foodOrigin: "Yogyakarta", foodName: "Gudeg", originCode: "YKT" }];
    var foodsList = [];
    let count = 10000000;
    while (count--) {
        foodsList.push(...chunk);
    }
    
    // @benchmark Peter's solution

    foodsList
      .reduce((collector, { foodOrigin, originCode = null }) => {

        if (originCode !== null && !collector.lookup.has(foodOrigin)) {

          collector.lookup.set(foodOrigin, true);
          collector.result.push({
            foodOrigin,
            originCode,
          });
        }
        return collector;

      }, { lookup: new Map, result: [] }).result;

    // @benchmark Nina's solution
    Array.from(
        foodsList.reduce((m, { foodOrigin, originCode }) => m.set(foodOrigin, originCode), new Map),
        ([foodOrigin, originCode]) => ({ foodOrigin, originCode })
    );

    // @benchmark Alexander's solution
    const map = new Map;
    for (let i = 0; i < foodsList.length; i++) {
        const item = foodsList[i];
        map.has(item.originCode) || map.set(item.originCode, item.foodOrigin);
    }

    Array.from(map, ([originCode, foodOrigin]) => ({ foodOrigin, originCode }));

    // @benchmark Nina's improved

    Array.from(
        foodsList.reduce((m, { foodOrigin, originCode }) => {
            m.has(foodOrigin) || m.set(foodOrigin, originCode);
            return m;
        }, new Map),
        ([foodOrigin, originCode]) => ({ foodOrigin, originCode })
    );


</script>
<script src="https://cdn.jsdelivr.net/gh/silentmantra/benchmark/loader.js"></script>