Javascript 调用promise上的resolve()不会更改其状态，状态仍将保持在待定状态

我有以下代码

import fetch, { Response } from "node-fetch"
import { joinCookieNameAndValue } from "../string-manipulation"
import item from "../../types/data-types/item"

const scan = (name: string, page: number): Promise<item | void> => new Promise(async (resolve, reject) => {
    const itemsRes: Response = await fetch(`url`, {
        method: "GET",
        headers: {
            Cookie: joinCookieNameAndValue("cookie-name", <string> process.env.COOKIE_VALUE)
        }
    })

    if (!itemsRes.ok) {
        return reject(new Error(`Could not fetch items: request failed with status code ${itemsRes.status}`));
    }

    const items: Array<item> = await itemsRes.json();
    const item_: item | undefined = items.find(i => i.name == name);

    if (items.length == 0) {
        return resolve();
    }

    if (!item_) {
        return scan(name, ++page);
    }

    resolve(item);
})

export default async (name: string) => scan(name, 1);

上面的promise 在另一个脚本中等待，但它之后的代码将永远不会运行，因为即使items.length == 0if语句中的代码运行，promise 也永远不会得到解析.