Javascript 如何根据列条件从二维数组返回唯一元素

发布于11月26日

我已经查看了this个，但它没有返回预期的结果，即:

[
  [4, "frente", 196],
  [5, "frente", 196]  
]

function getUniqueData(arr = [
  [4, "frente", 196],
  [4, "frente", 196],
  [5, "frente", 196]  
], uniqueCols = [0]) {
  const uniqueData = arr.filter((currentRow, i) => {
    const currentCombo = uniqueCols.map(index => currentRow[index]);
    return !arr.some((row, j) => {
      const combo = uniqueCols.map(index => row[index]);
      return combo.every((c1, k) => c1 === currentCombo[k]) && i !== j;
    });
  });
  return uniqueData;
}
console.log(getUniqueData())

推荐答案

From what I understand you are trying to remove duplicates. What you have tried removes all the entries that have the same column.
Here is an answer based on a similar thing but for objects

Here I filter out entries based on unique column combinations
Hope this was what you meant

function getUniqueData(arr = [
  [4, "frente", 196],
  [4, "frente", 196],
  [5, "frente", 196]  
], uniqueCols = [0]) {
  const uniqueData = arr.filter((currentRow, i, self) => {
    return i === self.findIndex((t) => {
        return uniqueCols.every((col) => t[col] === currentRow[col])
    })
  });
  return uniqueData;
}
console.log(getUniqueData())

更多 case

function getUniqueData(arr = [
  [4, "frente", 196],
  [4, "frente", 196],
  [5, "frente", 196]  
], uniqueCols = [1]) {
  const uniqueData = arr.filter((currentRow, i, self) => {
    return i === self.findIndex((t) => {
        return uniqueCols.every((col) => t[col] === currentRow[col])
    })
  });
  return uniqueData;
}
console.log(getUniqueData())

function getUniqueData(arr = [
  [4, "a", 196],
  [4, "frente", 196],
  [5, "frente", 196]  
], uniqueCols = [1]) {
  const uniqueData = arr.filter((currentRow, i, self) => {
    return i === self.findIndex((t) => {
        return uniqueCols.every((col) => t[col] === currentRow[col])
    })
  });
  return uniqueData;
}
console.log(getUniqueData())

function getUniqueData(arr = [
  [4, "frente", 196],
  [4, "frente", 196],
  [5, "frente", 196]  
], uniqueCols = [0,1]) {
  const uniqueData = arr.filter((currentRow, i, self) => {
    return i === self.findIndex((t) => {
        return uniqueCols.every((col) => t[col] === currentRow[col])
    })
  });
  return uniqueData;
}
console.log(getUniqueData())