Javascript 如何将搜索应用于字符串数组

发布于07月19日

在我的例子中，搜索应该遍历嵌套数组的前[1]个元素.

function massivs() {
        let array = [['a', 'mango', 'b','c'], ['d', 'applemango', 'e','f'],['k', 'mangoapple', 's','r']];
        let comp = ['apple', 'mango'];
        let ans = [];
        
        for (let i = 0; i < array.length; i++) {        
            for (el of array[i]) {
                if (comp.every(y => el.includes(y))) {
                    ans.push(el);
                }
            }
        }
        console.log(ans);
}

massivs();

[ 'applemango', 'mangoapple' ]


Expected Result [['d', 'applemango', 'e','f'],['k', 'mangoapple', 's','r']]

推荐答案

for of迭代数组中的项，因此它只推送包含在搜索值中的数组元素，如果在搜索中找到，则推送整个数组并打破循环

 function massivs() {
            let array = [['a', 'mango', 'b','c'], ['d', 'applemango', 'e','f'],['k', 'mangoapple', 's','r']];
            let comp = ['apple', 'mango'];
            let ans = [];
            
            for (let i = 0; i < array.length; i++) {        
                for (el of array[i]) {
                    if (comp.every(y => el.includes(y))) {
                        ans.push(array[i]);
                        break;
                    }
                }
            }
            console.log(ans);
    }

    massivs();