我需要能够在运行时合并两个(非常简单的)JavaScript对象.例如,我想:
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
obj1.merge(obj2);
//obj1 now has three properties: food, car, and animal
有没有一种内在的方法可以做到这一点?我不需要递归,也不需要合并函数,只需要平面对象上的方法.
我需要能够在运行时合并两个(非常简单的)JavaScript对象.例如,我想:
var obj1 = { food: 'pizza', car: 'ford' }
var obj2 = { animal: 'dog' }
obj1.merge(obj2);
//obj1 now has three properties: food, car, and animal
有没有一种内在的方法可以做到这一点?我不需要递归,也不需要合并函数,只需要平面对象上的方法.
ECMAScript 2018 Standard Method
你可以使用object spread:
let merged = {...obj1, ...obj2};
merged
现在是obj1
和obj2
的和.obj2
中的属性将覆盖obj1
中的属性.
/** There's no limit to the number of objects you can merge.
* Later properties overwrite earlier properties with the same name. */
const allRules = {...obj1, ...obj2, ...obj3};
下面也是此语法的MDN documentation.如果你使用的是巴别塔,你需要babel-plugin-transform-object-rest-spread插件才能工作.
ECMAScript 2015 (ES6) Standard Method
/* For the case in question, you would do: */
Object.assign(obj1, obj2);
/** There's no limit to the number of objects you can merge.
* All objects get merged into the first object.
* Only the object in the first argument is mutated and returned.
* Later properties overwrite earlier properties with the same name. */
const allRules = Object.assign({}, obj1, obj2, obj3, etc);
Method for ES5 and Earlier个
for (var attrname in obj2) { obj1[attrname] = obj2[attrname]; }
请注意,这将简单地添加obj2
到obj1
的所有属性,如果您仍然想要使用未修改的obj1
,那么这些属性可能不是您想要的.
如果你使用的框架在你的原型上到处都是垃圾,那么你必须通过hasOwnProperty
这样的判断来获得更丰富的知识,但这些代码将适用于99%的情况.
示例功能:
/**
* Overwrites obj1's values with obj2's and adds obj2's if non existent in obj1
* @param obj1
* @param obj2
* @returns obj3 a new object based on obj1 and obj2
*/
function merge_options(obj1,obj2){
var obj3 = {};
for (var attrname in obj1) { obj3[attrname] = obj1[attrname]; }
for (var attrname in obj2) { obj3[attrname] = obj2[attrname]; }
return obj3;
}