Java 插入中的JOOQ序列，设置为VS值

我有一张有顺序的简易桌. 当我在INSERTINT.SET方法中使用Sequence.nextval()时，一切正常. 当我在intertInto.Values方法中使用equence.nextval()时，只使用Sequence，再次指定end就可以了. 当我在INSERTINT.VALUES方法中使用Sequence.nextval()时，如果使用的不是Sequence，则会出现错误.

这样就可以了

        int w = dslContext
                .insertInto(APPOINTMENTTYPE)
                .set(APPOINTMENTTYPE.MC, 501559436L)
                .set(APPOINTMENTTYPE.ID, HIBERNATE_SEQUENCE.nextval())
                .set(APPOINTMENTTYPE.NAME, "test name")
                .set(APPOINTMENTTYPE.DESCRIPTION, "test description")
                .set(APPOINTMENTTYPE.BLUE, 255)
                .set(APPOINTMENTTYPE.GREEN, 255)
                .set(APPOINTMENTTYPE.RED, 255)
                .set(APPOINTMENTTYPE.REMINDERINTERVAL, 1)
                .execute();

这也可以.

        int x = dslContext.insertInto(APPOINTMENTTYPE, 
APPOINTMENTTYPE.ID).values(APPOINTMENTTYPE_SEQ.nextval()).execute();

这会产生错误Cannot resolve method 'values(Field<Long>, int)'

        int y = dslContext.insertInto(APPOINTMENTTYPE, APPOINTMENTTYPE.ID, APPOINTMENTTYPE.BLUE).values(APPOINTMENTTYPE_SEQ.nextval(), 255).execute();