Java 在 Linux 上的 shell 脚本中无法识别新行

我在Linux Ubuntu服务器上编写了一个shell 脚本. 我想在Java上运行一个shell 脚本.

在Linux服务器中运行shell 脚本会改变我编写它的方式，但不是通过Java.

我将向您展示Java代码、shell 脚本文件和捕获屏幕.

Java个

public class ShellScriptApplication {

    public static void main(String[] args) {

        String start = "start";
        String stop = "stop";
        String name = "";

        Scanner sc = new Scanner(System.in);
        System.out.print("start or stop? : ");
        String s = sc.nextLine();

        if(s.equals(start)) {
            System.out.print("시작하실 프로그램을 입력해주세요 [admin / ap / json / fixed] : ");
            name = sc.nextLine();
            openShell(start, name);
        } else if (s.equals(stop)) {
            System.out.print("종료하실 프로그램을 입력해주세요 [admin / ap / json / fixed] : ");
            name = sc.nextLine();
            openShell(stop, name);
        } else {
            System.out.println("wrong");
        }

    }

    public static String openShell(String status, String name)  {
        String result = "";

        String dir = "/data/GSLinkIN/app";

        String cdExec = "cd " + dir + " && ./"+ name + "-" + status + ".sh";

        String [] command = {"/bin/sh","-c", cdExec};
        ProcessBuilder processBuilder = new ProcessBuilder();
        processBuilder.command(command);

        try {
            // Run script
            Process process = processBuilder.start();

            // Read output
            StringBuilder output = new StringBuilder();
            BufferedReader reader = new BufferedReader( new InputStreamReader(process.getInputStream()));

            String line;
            while ((line = reader.readLine()) != null) {
                output.append(line);
            }
            if(output.toString().equals("")) {
                result = "success";
            }else {
                result = output.toString();
            }
        } catch (Exception e) {
            result = "fail";
        }
        System.out.println(result);

        return result;
    }

}

stop.sh个

#!/bin/sh

APP_NAME=linkin-admin-www-2.0.war
APP_PID=$(ps -ef | grep $APP_NAME | grep -v grep | awk '{print $2}')

echo "$APP_NAME (PID:$APP_PID)"
kill -9 $APP_PID
echo "$APP_NAME stopped"

When running a shell script using Java

When running directly on a Linux server个

即使我在Java上运行一个Shell脚本，我也想打印这个ID，然后得到一个新行.