如何在Java中将字节大小转换为人类可读的格式?
比如1024应该变成"1KB",1024*1024应该变成"1MB".
我有点厌倦了 for each 项目编写这种实用方法.在Apache Commons中有没有静态方法?
如何在Java中将字节大小转换为人类可读的格式?
比如1024应该变成"1KB",1024*1024应该变成"1MB".
我有点厌倦了 for each 项目编写这种实用方法.在Apache Commons中有没有静态方法?
Fun fact:这里发布的原始代码段是有史以来在堆栈溢出上复制最多的Java代码段,而且存在缺陷.它被修好了,但弄得一团糟.
本文的完整故事:The most copied Stack Overflow snippet of all time is flawed!
资料来源:Formatting byte size to human readable format | Programming.Guide
public static String humanReadableByteCountSI(long bytes) {
if (-1000 < bytes && bytes < 1000) {
return bytes + " B";
}
CharacterIterator ci = new StringCharacterIterator("kMGTPE");
while (bytes <= -999_950 || bytes >= 999_950) {
bytes /= 1000;
ci.next();
}
return String.format("%.1f %cB", bytes / 1000.0, ci.current());
}
public static String humanReadableByteCountBin(long bytes) {
long absB = bytes == Long.MIN_VALUE ? Long.MAX_VALUE : Math.abs(bytes);
if (absB < 1024) {
return bytes + " B";
}
long value = absB;
CharacterIterator ci = new StringCharacterIterator("KMGTPE");
for (int i = 40; i >= 0 && absB > 0xfffccccccccccccL >> i; i -= 10) {
value >>= 10;
ci.next();
}
value *= Long.signum(bytes);
return String.format("%.1f %ciB", value / 1024.0, ci.current());
}
SI BINARY
0: 0 B 0 B
27: 27 B 27 B
999: 999 B 999 B
1000: 1.0 kB 1000 B
1023: 1.0 kB 1023 B
1024: 1.0 kB 1.0 KiB
1728: 1.7 kB 1.7 KiB
110592: 110.6 kB 108.0 KiB
7077888: 7.1 MB 6.8 MiB
452984832: 453.0 MB 432.0 MiB
28991029248: 29.0 GB 27.0 GiB
1855425871872: 1.9 TB 1.7 TiB
9223372036854775807: 9.2 EB 8.0 EiB (Long.MAX_VALUE)