我想得到一个目录中的文件列表，但我想对它进行排序，以使最旧的文件排在第一位.我的解决方案是调用File.列出文件，然后根据文件 Select 列表.最后修改了，但我想知道是否有更好的方法.
编辑:根据建议，我目前的解决方案是使用匿名比较器:
File[] files = directory.listFiles();
Arrays.sort(files, new Comparator<File>(){
public int compare(File f1, File f2)
{
return Long.valueOf(f1.lastModified()).compareTo(f2.lastModified());
} });
I think your solution is the only sensible way. The only way to get the list of files is to use File.listFiles() and the documentation states that this makes no guarantees about the order of the files returned. Therefore you need to write a Comparator that uses File.lastModified() and pass this, along with the array of files, to Arrays.sort().