根据你的问题，答案是否定的.没有直接的方法.有关更多信息，请访问此处:
和
iPhone X的高度是2436像素
From Device Screen Sizes 和 resolutions:
From Device Screen Sizes 和 Orientations:
Swift 3 和 later:
if UIDevice().userInterfaceIdiom == .phone {
switch UIScreen.main.nativeBounds.height {
case 1136:
print("iPhone 5 or 5S or 5C")
case 1334:
print("iPhone 6/6S/7/8")
case 1920, 2208:
print("iPhone 6+/6S+/7+/8+")
case 2436:
print("iPhone X/XS/11 Pro")
case 2688:
print("iPhone XS Max/11 Pro Max")
case 1792:
print("iPhone XR/ 11 ")
default:
print("Unknown")
}
}
Objective-C:
if([[UIDevice currentDevice] userInterfaceIdiom] == UIUserInterfaceIdiomPhone) {
switch ((int)[[UIScreen mainScreen] nativeBounds].size.height) {
case 1136:
printf("iPhone 5 or 5S or 5C");
break;
case 1334:
printf("iPhone 6/6S/7/8");
break;
case 1920:
case 2208:
printf("iPhone 6+/6S+/7+/8+");
break;
case 2436:
printf("iPhone X/XS/11 Pro");
break;
case 2688:
printf("iPhone XS Max/11 Pro Max");
break;
case 1792:
printf("iPhone XR/ 11 ");
break;
default:
printf("Unknown");
break;
}
}
Xamarin.iOS:
if (UIDevice.CurrentDevice.UserInterfaceIdiom == UIUserInterfaceIdiom.Phone) {
if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1136) {
Console.WriteLine("iPhone 5 or 5S or 5C");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1334) {
Console.WriteLine("iPhone 6/6S/7/8");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1920 || (UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2208) {
Console.WriteLine("iPhone 6+/6S+/7+/8+");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2436) {
Console.WriteLine("iPhone X, XS, 11 Pro");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 2688) {
Console.WriteLine("iPhone XS Max, 11 Pro Max");
} else if ((UIScreen.MainScreen.Bounds.Height * UIScreen.MainScreen.Scale) == 1792) {
Console.WriteLine("iPhone XR, 11");
} else {
Console.WriteLine("Unknown");
}
}
根据您的问题，如下所示:
或者使用screenSize.height作为浮点型812.0f，而不是整型812.
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPhone) {
CGSize screenSize = [[UIScreen mainScreen] bounds].size;
// 812.0 on iPhone X, XS
// 896.0 on iPhone XS Max, XR.
if (screenSize.height >= 812.0f)
NSLog(@"iPhone X");
}
有关更多信息，请参阅iOS人机界面指南中的以下页面:
Swift:
用topNotch检测:
If anyone considering using notch to detect iPhoneX, mind that on "l和scape" its same for all iPhones.
var hasTopNotch: Bool {
if #available(iOS 13.0, *) {
return UIApplication.shared.windows.filter {$0.isKeyWindow}.first?.safeAreaInsets.top ?? 0 > 20
}else{
return UIApplication.shared.delegate?.window??.safeAreaInsets.top ?? 0 > 20
}
return false
}
Objective-C:
- (BOOL)hasTopNotch {
if (@available(iOS 13.0, *)) {
return [self keyWindow].safeAreaInsets.top > 20.0;
}else{
return [[[UIApplication sharedApplication] delegate] window].safeAreaInsets.top > 20.0;
}
return NO;
}
- (UIWindow*)keyWindow {
UIWindow *foundWindow = nil;
NSArray *windows = [[UIApplication sharedApplication]windows];
for (UIWindow *window in windows) {
if (window.isKeyWindow) {
foundWindow = window;
break;
}
}
return foundWindow;
}
UPDATE:
不要使用userInterfaceIdiom属性来标识设备类型，如documentation for userInterfaceIdiom所述:
For universal applications, you can use this property to tailor the behavior of your application for a specific type of device. For example, iPhone 和 iPad devices have different screen sizes, so you might want to create different views 和 controls based on the type of the current device.
也就是说，此属性仅用于标识正在运行的应用程序的视图样式.然而，iPhone应用程序(不是通用的)可以通过应用程序store 安装在iPad设备上，在这种情况下，userInterfaceIdiom也会返回UIUserInterfaceIdiomPhone.
正确的方法是通过uname获取机器名称.有关详细信息，请查看以下内容: