Go 如何在出现错误时停止从通道读取

errroup.WithContext()可能是最好的方法(正如你所猜的那样).This answer值得一读；它提供了一个全面的解释(我不打算重复了！)

然而，由于这可能很难理解，这里有一个使用您的代码(playground)的解决方案:

package main

import (
    "context"
    "fmt"
    "time"

    "golang.org/x/sync/errgroup"
)

func main() {
    const threads = 3

    ch := make(chan int, threads)

    eg, ctx := errgroup.WithContext(context.Background())
    for i := 0; i < threads; i++ {
        i := i
        eg.Go(func() error {
            fmt.Printf("Thread %d: STARTED\n", i)
            for n := range ch {
                fmt.Printf("Thread %d: GOT=%d\n", i, n)
                time.Sleep(time.Duration(1) * time.Second)
                // Simulate failed thread
                if n == 2 {
                    fmt.Printf("Thread %d: FAILED\n", i)
                    return fmt.Errorf("Thread %d: FAILED", i)
                }
                // For the purpose of this example we will just check the context after
                // doing the work.
                if ctx.Err() != nil {
                    fmt.Printf("Thread %d: Quiting due to context\n", i)
                    return fmt.Errorf("Thread %d: Context cancelled: ", i)
                }
            }
            return nil
        })
    }

    // We want to stop sending new work if there is a failure (otherwise `ch <- i` will block permanently);
sendLoop:
    for i := 0; i < 9; i++ {
        select {
        case ch <- i:
        case <-ctx.Done():
            fmt.Printf("stopped\n")
            break sendLoop // Just exit the loop if something goes wrong (you may want to do something else here)
        }
    }
    close(ch) // Note: Important that this happens even if there is an error (otherwise `for n := range ch` may block, leaking goroutines)
    fmt.Printf("all sent\n")
    if err := eg.Wait(); err != nil {
        panic(err)
    }
}