当函数返回一个函数时，为什么 Go 泛型会失败

我刚刚开始在Go上try 泛型，我遇到了一种情况，我不完全理解它为什么会失败.

我重构了以下函数，如下所示:

func PositivePercentageAbove(above int) func(list []uint8) bool {
    return func(list []uint8) bool {
        acum := 0
        for _, x := range list {
            acum += int(x)
        }
        return (float64(acum) / float64(len(list)) * 100) >= float64(above)
    }
}

进入这一阶段:

func PositivePercentageAbove[T constraints.Integer](above int) func(list []T) bool {
    return func(list []T) bool {
        acum := 0
        for _, x := range list {
            acum += int(x)
        }
        return (float64(acum) / float64(len(list)) * 100) >= float64(above)
    }
}

此函数的单元测试失败，错误为:tests/utils/NumberUtils_test.go:82:50: cannot infer T .消息来源为:

func Test_TruePercentageAbove(t *testing.T) {
    tables := []struct {
        percentage int
        list       []uint8
        output     bool
    }{
        {percentage: 100, list: []uint8{1, 1, 1, 1}, output: true},
        {percentage: 100, list: []uint8{1, 1, 0, 1}, output: false},
        {percentage: 80, list: []uint8{1, 1, 1, 1, 0}, output: true},
        {percentage: 90, list: []uint8{1, 1, 1, 1, 0}, output: false},
        {percentage: 100, list: []uint8{1, 1, 1, 1, 0}, output: false},
        {percentage: 40, list: []uint8{0, 1, 0, 1, 0, 1}, output: true},
        {percentage: 60, list: []uint8{0, 1, 0, 1, 0, 1}, output: false},
        {percentage: 70, list: []uint8{0, 1, 0, 1, 0, 1}, output: false},
    }

    for _, table := range tables {
        result := utils.PositivePercentageAbove(table.percentage)(table.list)

        if result != table.output {
            t.Errorf("Slice %v with percentage above %v expected to return %v but returned %v", table.list, table.percentage, table.output, result)
        }
    }
}

我已经将类似的函数从int改为泛型，我不确定为什么这个函数特别不起作用.我认为这可能与返回另一个函数的函数有关，但我不知props 体原因.谢谢.