在 Go 中以字符串形式访问 HTTP 响应

发布于07月30日

我想解析Web请求的响应，但我无法将其作为字符串访问.

func main() {
    resp, err := http.Get("http://google.hu/")
    if err != nil {
        // handle error
    }
    defer resp.Body.Close()
    body, err := ioutil.ReadAll(resp.Body)

    ioutil.WriteFile("dump", body, 0600)

    for i:= 0; i < len(body); i++ {
        fmt.Println( body[i] ) // This logs uint8 and prints numbers
    }

    fmt.Println( reflect.TypeOf(body) )
    fmt.Println("done")
}

如何以字符串形式访问响应？ioutil.WriteFile将响应正确写入文件.

我已经判断了软件包参考，但它没有真正的帮助.

推荐答案

bs := string(body)应该足够给你一根绳子了.

从那里，可以将其用作常规字符串.

A bit as in this thread
(updated after Go 1.16 -- Q1 2021 -- ioutil deprecation: ioutil.ReadAll() => io.ReadAll()):

var client http.Client
resp, err := client.Get(url)
if err != nil {
    log.Fatal(err)
}
defer resp.Body.Close()

if resp.StatusCode == http.StatusOK {
    bodyBytes, err := io.ReadAll(resp.Body)
    if err != nil {
        log.Fatal(err)
    }
    bodyString := string(bodyBytes)
    log.Info(bodyString)
}

另请参见GoByExample.

As commented below (and in zzn's answer), this is a conversion (see spec).
See "How expensive is []byte(string)?" (reverse problem, but the same conclusion apply) where zzzz mentioned:

有些转换与强制转换相同，比如uint(myIntvar)，它只是重新解释到位的位.

Sonia增加了:

Making a string out of a byte slice, definitely involves allocating the string on the heap. The immutability property forces this.
Sometimes you can optimize by doing as much work as possible with []byte and then creating a string at the end. The bytes.Buffer type is often useful.