Django 如何在uwsgi中创建单个日志(log)文件

发布于10月16日

我正在为Django应用程序使用下面的uwsgi日志(log)配置文件.它创建了两个日志(log)文件:

访问日志(log)-2023-10-13.log
APP_LOG-2023-10-13.log

现在，我想再创建一个名为all_logs-2023-10-13.log的日志(log)文件，其中包含两个access + app个日志(log)文件数据.有没有办法创造出这样的东西？

[uwsgi]
master = true
http-socket = xyz_port
memory-report = true
module = demo_app.wsgi
...
...
...

log-date = %%d/%%m/%%Y %%H:%%M:%%S %%Z
logformat-strftime = true
logger = stdio
log-format = %(addr) - %(user) [%(ftime)] "%(method) %(uri) %(proto)" %(status) %(size) %(referer) %(uagent) %(pid)
req-logger = file:/var/log/demo_app/access_log-@(exec://date +%%Y-%%m-%%d).log
logger = file:/var/log/demo_app/app_log-@(exec://date +%%Y-%%m-%%d).log
log-reopen = true

推荐答案

The uWSGI documentation outlines the use of --log-route for directing log messages based on regular expressions to different destinations.
However, it does not provide a direct method to combine logs from different sources into a single file.

您需要创建一个简单的脚本来合并日志(log)文件，该脚本可以计划为每天运行以将access_log和app_log合并为all_logs.

类似于:

import datetime

def merge_logs():
    date_suffix = datetime.datetime.now().strftime('%Y-%m-%d')
    with open(f'/var/log/demo_app/access_log-{date_suffix}.log', 'r') as access_log, \
         open(f'/var/log/demo_app/app_log-{date_suffix}.log', 'r') as app_log, \
         open(f'/var/log/demo_app/all_logs-{date_suffix}.log', 'a') as all_logs:
        for line in access_log:
            all_logs.write(line)
        for line in app_log:
            all_logs.write(line)

if __name__ == "__main__":
    merge_logs()