你好，我在Django使用基于类的视图，我想创建一个搜索表单，让用户在我的应用程序中找到他们自己最喜欢的产品，并带有多个过滤器和排除项，但我做不到.我的代码在这里，如果任何人可以修改它以使其正确，请帮助我:

Models.py

from django.db.models import models
from django.core.validators import RegexValidators


class Product(models.Model):
    num=RegexValidators(r'^[0-9a-zA-Z]*$')
    title = models.CharField(max_length=100)
    embed_id = models.CharField(max_length=15, validators=[num])
    description = models.TextField(null=True, blank=True)

Forms.py

from django import forms


class ProductSearchForm(forms.Form):
    title = forms.CharField(required=False)
    embed_id = forms.CharField(required=False)
    description = forms.CharField(required=False)

Views.py

from django.views.generic import ListView
from .models import Product
from .forms import ProductSearchForm


class ProductListView(ListView):
    model = Product
    form_class = ProductSearchForm
    template_name = 'pages/product/list_products.html'

    def get_queryset(self):
       queryset = super().get_queryset()
       form = self.form_class(self.request.GET)
       if form.is_valid():
           title = form.cleaned_data.get('title')
           embed_id = form.cleaned_data.get('embed_id')
           description = form.cleaned_data.get('description')
           if title:
              queryset = queryset.filter(title__icontains=title)
           if embed_id:
              queryset = queryset.filter(embed_id__icontains=embed_id)
           if description:
              queryset = queryset.filter(description__icontains=description)
           return queryset

   def get_context_data(self, [**kwargs):
      context = super().get_context_data(self, **kwargs):
      context['form'] = self.form_class(self.request.GET)
      return context

Product_earch.html

<form method="get" action="{% url 'product_list' %}">
{{ form.as_p }}
<input type="submit" value="Search">
</form>
{% if object_list %}
<ul>
{% for product in object_list %}
<li>{{ product.title }}</li>
{% endfor %}
</ul>
{% else %}
<p>No product found.</p>
{% endif %}

我知道如何在基于函数的视图中处理这个问题，但我想创建它的Generic.listview.