Csharp 使用yaml将Azure函数代码部署到FunctionApp插槽时出现问题(zip未找到)

我正在用C#构建Azure函数，并希望使用管道进行部署. 我做了一次，测试，然后发布. 然后，对于每个ENV，我运行一个bicep文件来设置基础设施，并在我希望将发布的Function Code部署到(单个)Function App之后立即运行.

我在try 从发布的zip文件进行部署时遇到了一个错误.文件找不到了.我做错了什么？

发布文件示例:

[命令]/usr/bin/zip—r/home/vsts/work/1/s/www.example.com

(日志(log)行似乎合理)

看到的错误:

##[error]Error: No package found with specified pattern: /home/vsts/work/1/a/*.zip
Check if the package mentioned

请注意，我们从/1/s发布，并try 在/1/a中找到它

该构建具有"附加"工件，如"drop/www.example.com (11MB的文件似乎合理)

yaml线发布:

- task: DotNetCoreCLI@2
  displayName: "dotnet publish"
  inputs:
    command: publish
    arguments: '--configuration Release --output publish_output'
    projects: 'src/**/*.csproj'
    publishWebProjects: false
    modifyOutputPath: false
    zipAfterPublish: false
- task: ArchiveFiles@2
  displayName: "Archive files (into zip)"
  inputs:
    rootFolderOrFile: "$(System.DefaultWorkingDirectory)/publish_output"
    includeRootFolder: false
    archiveFile: "$(System.DefaultWorkingDirectory)/build$(Build.BuildId).zip"
- task: PublishBuildArtifacts@1
  displayName: "Publish build artifacts"
  inputs:
    PathtoPublish: '$(System.DefaultWorkingDirectory)/build$(Build.BuildId).zip'

YAML线部署:

- task: AzureFunctionApp@1 # Add this at the end of your file
  displayName: 'Deploy Function code to FunctionApp Slot'
  inputs:    
    azureSubscription: 'ServiceConnection'
    appType: functionAppLinux # default is functionApp
    appName: 'f2404dev-app'
    package: '$(System.ArtifactsDirectory)/**/*.zip'