Csharp Monty Hall游戏节目模拟给我5050的结果

我想为Monty Hall问题创建一个简单的模拟，作为一个有趣的，快速的辅助项目.我的计划是创建完整的游戏，有可点击的门和所有的形式，但我首先想创建一种方法来模拟尽可能多的游戏，我想证明给自己，切换门有66%的机会获胜.问题是，我每次都有50/50的赔率.

有人能发现我的模拟有什么问题吗？当我增加门的数量时，切换门后获胜的几率就会增加.然而，有3个门，我总是得到大约50/50，所以我知道有一个问题与我的代码.

private void simulateButton_Click(object sender, EventArgs e)
{
    int wins = 0;
    int losses = 0;
    int attempts = 0;
    int numberOfDoors = 3;

    // Main game loop. Number of simulations can easily be changed from 1000
    for (int games = 0; games < 1000; games++)
    {                               
        List<Door> doors = new List<Door>();
        for (int i = 0; i < numberOfDoors; i++)
        {
            doors.Add(new Door
            {
                Contents = "goat",
                Opened = false,
                PlayerChoice = false,
            });     
        }


        // Randomly pick a door for the car to be in
        Random random = new Random();
        int doorNumWithCar = random.Next(0, numberOfDoors - 1);
        doors[doorNumWithCar].Contents = "car";


        // I set player choice to always be door #1 to make it simpler
        doors[0].PlayerChoice = true;


        // Monty randomly removes one of the 2 doors not chosen by the player.
        // (obviously, he doesn't remove the door with the car)
        int doorMontyOpens;
        while (doors.Count != 2)
        {
            doorMontyOpens = -1;
            while (doorMontyOpens == -1)
            {
                int possibleDoorToBeShown = random.Next(1, doors.Count);

                if (doors[possibleDoorToBeShown].Contents != "car")
                {
                    doorMontyOpens = possibleDoorToBeShown;
                }
            }
            
            // I just remove the door since that is essentially what Monty Hall is doing when 
            // He reveals one of the goats
            doors.RemoveAt(doorMontyOpens);
        }


        // Since player choice is always door #1 (index 0) and there are only two doors left,
        // we only need to check door #2 at index 1. If it has the car, it is a win. If not, a loss.
        // This simulation only tests the case in which the player changes doors after Monty reveals
        // a door. So it SHOULD usually have about 667 wins and 333 losses. Why do I get 50/50???
        if (doors[1].Contents == "car")
        {
            wins++;
        }
        else
        {
            losses++;
        }

        attempts++;
        this.winsTextbox.Text = $"{wins}";
        this.lossesTextbox.Text = $"{losses}";
        this.attemptsTextbox.Text = $"{attempts}";                
    }

    MessageBox.Show("Done!");
}

public class Door
{
    public string Contents { get; set; }
    public bool Opened { get; set; }
    public bool PlayerChoice {  get; set; }
}

别介意代码的蹩脚.这是一个超级快速和肮脏的模拟.代码的每一段注释都在注释中.谢谢！