我正在try 创建一个平台驱动程序,我有以下代码
模块
// SPDX-License-Identifier: GPL-2.0
#include <linux/module.h>
#include <linux/init.h>
#include <linux/pm.h>
#include <linux/of_device.h>
#include <linux/fb.h>
static int simple_probe(struct platform_device *pdev)
{
printk(KERN_ERR "SIMPLE: %s\n", "Probing");
return 0;
}
const struct of_device_id simple_of_match[] = {
{
.compatible = "example,simple",
},
{ /*End of List*/ },
};
struct platform_driver simple_driver = {
.probe = simple_probe,
.driver = {
.name = "simple",
.owner = THIS_MODULE,
.of_match_table = simple_of_match
}
};
static int __init init(void)
{
if (platform_driver_register(&simple_driver)) {
printk(KERN_ERR "SIMPLE: %s\n", "Registerered");
} else {
printk(KERN_ERR "SIMPLE: %s\n", "Failed");
}
return 0;
}
static void __exit deinit(void)
{
platform_driver_unregister(&simple_driver);
}
module_init(init);
module_exit(deinit);
MODULE_DESCRIPTION("Simple Platform driver");
MODULE_AUTHOR("Bret Joseph Antonio <bret@binclab.com>");
MODULE_LICENSE("GPL");
我的设备树似乎没有运行覆盖,因此设备状态为OK.它仍然没有运行探测回调.
设备树
/dts-v1/;
/ {
simple@0 {
compatible = "example,simple";
pinctrl-names = "lcm_rst_out1_gpio", "lcm_rst_out0_gpio";
pinctrl-0 = <&PHANDLE1>;
pinctrl-1 = <&PHANDLE2>;
status = "okay";
};
};
我希望内核注册我的驱动程序,然后运行探测函数,但代码
if (platform_driver_register(&simple_driver) == 0) {
printk(KERN_ERR "SIMPLE: %s\n", "Registered");
} else {
printk(KERN_ERR "SIMPLE: %s\n", "Failed");
}
返回[ 0.178889] SIMPLE: Registered
,但探测函数保持静默.探测功能依赖于什么?
它是否应该在发现设备树中的 node 后立即运行探测?