C++ 使用 ANSI 转义序列获取终端大小

#include <stdio.h>
#include <termios.h>
#include <unistd.h>
#include <ctype.h>

#define SIZE 100

int main ( void) {
    char in[SIZE] = "";
    int each = 0;
    int ch = 0;
    int rows = 0;
    int cols = 0;
    struct termios original, changed;

    // change terminal settings
    tcgetattr( STDIN_FILENO, &original);
    changed = original;
    changed.c_lflag &= ~( ICANON | ECHO);
    changed.c_cc[VMIN] = 1;
    changed.c_cc[VTIME] = 0;
    tcsetattr( STDIN_FILENO, TCSANOW, &changed);

    printf ( "\033[2J"); //clear screen

    printf ( "\033[9999;9999H"); // cursor should move as far as it can

    printf ( "\033[6n"); // ask for cursor position
    while ( ( ch = getchar ()) != 'R') { // R terminates the response
        if ( EOF == ch) {
            break;
        }
        if ( isprint ( ch)) {
            if ( each + 1 < SIZE) {
                in[each] = ch;
                each++;
                in[each] = '\0';
            }
        }
    }

    printf ( "\033[1;1H"); // move to upper left corner
    if ( 2 == sscanf ( in, "[%d;%d", &rows, &cols)) {
        printf ( "%d rows\n", rows);
        printf ( "%d cols\n", cols);
    }

    // restore terminal settings
    tcsetattr( STDIN_FILENO, TCSANOW, &original);

    return 0;
}