remove repeated elements in array javascript

// You can find 6 methods to remove duplicated elements in js array
// here on this website:
// https://www.geeksforgeeks.org/how-to-remove-duplicate-elements-from-javascript-array/// how to remove duplicates from array in javascript
// 1. filter()
let num = [1, 2, 3, 3, 4, 4, 5, 5, 6];
let filtered = num.filter((a, b) => num.indexOf(a) === b)
console.log(filtered);
// Result: [ 1, 2, 3, 4, 5, 6 ]

// 2. Set()
const removeDuplicates = (arr) => [...new Set(arr)];
console.log(removeDuplicates([1, 2, 3, 3, 4, 4, 5, 5, 6]));
// Result: [ 1, 2, 3, 4, 5, 6 ]const myArray = [2,5,6,2,2,4,5,3,3];

const uniqueArray = [...new Set(myArray)];

console.log(uniqueArray);// for TypeScript and JavaScript
const initialArray = ['a', 'a', 'b',]
finalArray = Array.from(new Set(initialArray)); // a, buniqueArray = a.filter(function(item, pos) {
    return a.indexOf(item) == pos; 
})
var myArr = [1, 2, 2, 2, 3];
var mySet = new Set(myArr);
myArr = [...mySet];
console.log(myArr);
// 1, 2, 3unique = [...new Set(arr)];   // where arr contains duplicate elementsuniqueArray = a.filter(function(item, pos) {
    return a.indexOf(item) == pos;
})
function onlyUnique(value, index, self) {
  return self.indexOf(value) === index;
}

// usage example:
var a = ['a', 1, 'a', 2, '1'];
var unique = a.filter(onlyUnique);

console.log(unique); // ['a', 1, 2, '1']function removeDuplicates(arr) {
  const map = new Map();
  const result = [];

  for (const item of arr) {
    if (!map.has(item)) {
      map.set(item, true);
      result.push(item);
    }
  }

  return result;
}

const array = [1, 2, 3, 3, 4, 4, 5];
const uniqueArray = removeDuplicates(array);
console.log(uniqueArray); // Output: [1, 2, 3, 4, 5][...new Set(['1','1','2','2','3','3'])]
//this will return a new array with the unique primitive values
//I guess doing this with objects will require implementing equality method.
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