size of array
#include <bits/stdc++.h>
using namespace std;
int main()
{
int arr[] = {1, 2, 3, 4, 5};
int n = sizeof(arr)/sizeof(arr[0]);
return 0;
}Source: www.geeksforgeeks.org
javascript size array
let array = [1, 2, 3]; console.log(array.length);
length of array
//The length property provides an easy way to append a new element to an array: const fruits = ["Banana", "Orange", "Apple", "Mango"]; fruits[fruits.length] = "Kiwi" // >> ["Banana", "Orange", "Apple", "Mango" , "Kiwi"] //if you find this answer is useful , //upvote ⇑⇑ , so the others can benefit also . @mohammad alshraideh ( ͡~ ͜ʖ ͡°)
size of array
// Alternately, use the containers from the STL, e. g. std::array or std::vector. // These containers behave very similar to standard arrays, but you can query their // size at runtime, no problem. std::vector<int> array; array.pushback(2); array.pushback(7); array.pushback(344); array.pushback(45); array.pushback(89); array.pushback(28); std::size_t length = array.size(); // easy!
Source: www.codeproject.com
size of array
int array[] = {4,78,3,7,9,2,56,2,76,23,6,2,1,645};
std::size_t length = sizeof(array)/sizeof(int); // see solution 1Source: www.codeproject.com
length of array
int a[20]; int length; length = sizeof(a) / sizeof(int);
size of array
#include <stdio.h>
#include <stdlib.h>
void printSizeOf(int intArray[]);
void printLength(int intArray[]);
int main(int argc, char* argv[])
{
int array[] = { 0, 1, 2, 3, 4, 5, 6 };
printf("sizeof of array: %d\n", (int) sizeof(array));
printSizeOf(array);
printf("Length of array: %d\n", (int)( sizeof(array) / sizeof(array[0]) ));
printLength(array);
}
void printSizeOf(int intArray[])
{
printf("sizeof of parameter: %d\n", (int) sizeof(intArray));
}
void printLength(int intArray[])
{
printf("Length of parameter: %d\n", (int)( sizeof(intArray) / sizeof(intArray[0]) ));
}
Source: stackoverflow.com
size of array
If all you have is the pointer to the first element then you can't:
int array[6]= { 1, 2, 3, 4, 5, 6 };
void main()
{
int *parray = &(array[0]);
int len=sizeof(array)/sizeof(int);
printf("Length Of Array=%d\n", len);
len = sizeof(parray);
printf("Length Of Array=%d\n", len);
getch();
}
// output: Will give two different values: 6, and 4.Source: www.codeproject.com
size of array
// If you have s statically allocated array, you can determine the number of elements //from the arrays name. However, if that is the case, and you don't use C++ functionality, //then most likely there wouldn't be a need for this in the first place. int array[10]; std::size_t length = 10; // big surprise, that number is right in the definition!
Source: www.codeproject.com
Size Of Array
<?php
$array = array(
"f" => "f",
"b" => "b",
);
print(sizeOf($array))
?>
get array size
// C++ program to find size
// of an array by using a
// pointer hack
#include <bits/stdc++.h>
using namespace std;
int main()
{
int arr[] = { 1, 2, 3, 4, 5, 6 };
int size = *(&arr + 1) - arr;
cout << "Number of elements in arr[] is " << size;
return 0;
}Source: www.geeksforgeeks.org