所以我在做一个小项目，我试着从用户那里获取信息
e = Entry(window, width=40, borderwidth=3, font='Arial 20')
e.place(rely=0.2, relx=0.24)
r1 = Label(window, text="good", font='Arial 20')
def s_command():
x = ["egg","milk","rice","salt"]
s_input = e.get().split(" ")
for s_input in x:
r1.pack()
S_button = Button(window, text="Search", font='Arial 22', width=8, command=s_command)
S_button.place(rely=0.25, relx=0.4)
这里需要一个嵌套循环，因为需要判断用户是否输入了多个项目，以及列表中是否存在任何项目.
def s_command():
x = ["egg","milk","rice","salt"]
s_input = e.get().split(" ")
for inp in s_input: # Go through input list
for item in x: # Go through items list
if inp == item: # If an input is same as item
r1.pack() # Show the widget
break # Stop the loop because you want to check if any item matches
else:
r1.pack_forget() # Remove the label
# Make the nested loop break the outer loop
else:
continue
break
如果你只需要在列表中勾选一个项目，那么这会容易得多:
def s_command():
x = ["egg", "milk", "rice", "salt"]
s_input = e.get() # Only single item so no need to split
if s_input in x:
r1.pack()
else:
r1.pack_forget()