Json Jolt 规范将父对象中的所有键应用于数组中的所有对象

给定一个输入数组，该数组包含包含各种关键点的对象和active_candidates_group个关键点，其中该关键点是候选对象的数组，创建一个新的输出数组，其中每个候选对象与来自父对象的关键点相结合.

请务必注意以下几点:

1. 父对象中有数百个关键点，对它们进行硬编码并不理想.
2. 父对象的关键点的顺序并不重要.
3. 父对象和候选对象之间不应该有重复的关键点.

输入

[
  {
    "id": 123,
    "name": "foo",
    // { hundreds of other keys }
    "active_candidates_group": [
      {
        "person_id": 123,
        "person_name": "john"
        // { many fields specific to ‘candidate’ —no duplicates to parent expected }
      },
      {
        "person_id": 321,
        "person_name": "bob"
        // { many fields specific to ‘candidate’ —no duplicates to parent expected }
      }
    ]
  }
]

期望输出

[
   {
      "id": 123,
      "name": "foo",
      // { hundreds of other keys from parent }
      "person_id": 123,
      "person_name": "john"
      // { other candidate fields }
   },
   {
      "id": 123,
      "name": "foo",
      // { hundreds of other keys from parent }
      "person_id": 321,
      "person_name": "bob"
      // { other candidate fields }
   }
]

到目前为止，我try 的是:

[
  {
    "operation": "shift",
    "spec": {
      "*": { // Iterate for each object in the input array
        "active_candidates_group": { // Match 'active_candidates_group' key
          "*": { // Iterate for each object inside 'active_candidates_group'
            "@2": "&2[&1]", // Copy all keys from the parent object to the same index in the output array
            "*": "&2[&1].&" // Copy the current object to its corresponding index in the output array
          }
        }
      }
    }
  },
  {
    "operation": "remove",
    "spec": {
      "active_candidates_group": {
        "*": {
          "active_candidates_group": ""
        }
      }
    }
  }
]