Jquery 将每 3 个 div 包装在一个 div 中

发布于07月30日

Is it possible to use nth-child selectors to wrap 3 divs using .wrapAll? I can't seem to work out the correct equation.

so...

<div>
        <div></div>
        <div></div>
        <div></div>
        <div></div>
        <div></div>
        <div></div>
</div>

becomes...

<div>
   <div class="new">
        <div></div>
        <div></div>
        <div></div>
   </div>
   <div class="new">
        <div></div>
        <div></div>
        <div></div>
   </div>
</div>

推荐答案

You can do it with .slice(), like this:

var divs = $("div > div");
for(var i = 0; i < divs.length; i+=3) {
  divs.slice(i, i+3).wrapAll("<div class='new'></div>");
}

You can try out a demo here, all we're doing here is getting the elements you want to wrap and looping through them, doing a .wrapAll() in batches of 3 then moving to the next 3, etc. It will wrap 3 at a time and however many are left at the end, e.g. 3, 3, 3, 2 if that's the case.