简化 JavaScript

我目前是一名网络开发人员训练营的学生，我正在做一个项目.我知道有一种方法可以简化这个函数，但我似乎无法掌握它.有什么方法可以将整个过程简化为一个for循环，这样我就不必对每个元素都这样做了？我正在调用一个天气API，并将它们应用于HTML.另外，由于某些原因，JQuery不允许我使用$，所以我使用querySelector.

HTML个

 <div class="row bottom">
   <div class="col"><span class="subtitle">-Temperature-</span></div>
   <div class="col">
     <div class="row" id="date1">Sun</div>
     <div class="row data" id="date1Temp"><b>-4&deg;</b></div>
   </div>
   <div class="col">
     <div class="row" id="date2">Mon</div>
     <div class="row data" id="date2Temp"><b>-5&deg;</b></div>
   </div>
   <div class="col">
     <div class="row" id="date3">Tue</div>
     <div class="row data" id="date3Temp"><b>-10&deg;</b></div>
   </div>
   <div class="col">
     <div class="row" id="date4">Wed</div>
     <div class="row data" id="date4Temp"><b>-4&deg;</b></div>
   </div>
   <div class="col">
     <div class="row" id="date5">Thu</div>
     <div class="row data" id="date5Temp"><b>-2&deg;</b></div>
   </div>
   <div class="col">
     <hr />
   </div>
 </div>

JS个

let fiveDayWeather = function (weatherValue) {
  const date1 = document.querySelector("#date1");
  const date2 = document.querySelector("#date2");
  const date3 = document.querySelector("#date3");
  const date4 = document.querySelector("#date4");
  const date5 = document.querySelector("#date5");

  const date1Temp = document.querySelector("#date1Temp");
  const date2Temp = document.querySelector("#date2Temp");
  const date3Temp = document.querySelector("#date3Temp");
  const date4Temp = document.querySelector("#date4Temp");
  const date5Temp = document.querySelector("#date5Temp");

  let todaysMonth = dayjs().$M;
  let tomorrow = dayjs().$D + 1;
  let twoDaysAfter = dayjs().$D + 2;
  let threeDaysAfter = dayjs().$D + 3;
  let fourDaysAfter = dayjs().$D + 4;
  let fiveDaysAfter = dayjs().$D + 5;

  date1.innerText = `${todaysMonth}/${tomorrow}`;
  date1Temp.innerText = weatherValue.list[1].main.temp + "\u00B0 F";
  date2.innerText = `${todaysMonth}/${twoDaysAfter}`;
  date2Temp.innerText = weatherValue.list[2].main.temp + "\u00B0 F";
  date3.innerText = `${todaysMonth}/${threeDaysAfter}`;
  date3Temp.innerText = weatherValue.list[3].main.temp + "\u00B0 F";
  date4.innerText = `${todaysMonth}/${fourDaysAfter}`;
  date4Temp.innerText = weatherValue.list[4].main.temp + "\u00B0 F";
  date5.innerText = `${todaysMonth}/${fiveDaysAfter}`;
  date5Temp.innerText = weatherValue.list[5].main.temp + "\u00B0 F";