从 javascript t typescript 函数转换扩展运算符

我不能把那段代码从Java脚本转换成打字脚本.

问题是转换...扩散运算符.

function calculateCombinations(first, next, ...rest) {

  if (rest.length) {
    next = calculateCombinations(next, ...rest);
  }


  return first.flatMap(a => next.map(b => [a, b].flat()));
}


a1 = ['A', 'B']
a2 = ['+', '-']
a3 = ['1', '2']
a4 = ['X', 'Y', 'Z']
// Show possibile combinations
calculateCombinations(a1, a2, a3, a4); // give me an array of 24 combinations

Attempt 至 conversion 至 TS:个

  function calculateCombinationsTS(first: any[], next: any[], ...rest: any[]) {
    if (rest.length) {
        next = calculateCombinationsTS(next, ...rest);
    }

   return first.flatMap(a => next.map(b => [a, b].flat()));
  }

TS2556: A spread argument must either have a tuple type or be passed 至 a rest parameter.个

如果我改变了

 next = calculateCombinationsTS(next, ...rest);

至

 next = calculateCombinationsTS(next, rest);

该函数给出了一个错误结果，因为REST是作为数组的数组传递的，而不是参数列表

Example of output:个

nCombo = (a1 * a2 * a3 * a4) = 24 possibilities
[
  [ 'A', '+', '1', 'X' ], [ 'A', '+', '1', 'Y' ],
  [ 'A', '+', '1', 'Z' ], [ 'A', '+', '2', 'X' ],
  [ 'A', '+', '2', 'Y' ], [ 'A', '+', '2', 'Z' ],
  [ 'A', '-', '1', 'X' ], [ 'A', '-', '1', 'Y' ],
  [ 'A', '-', '1', 'Z' ], [ 'A', '-', '2', 'X' ],
  [ 'A', '-', '2', 'Y' ], [ 'A', '-', '2', 'Z' ],
  [ 'B', '+', '1', 'X' ], [ 'B', '+', '1', 'Y' ],
  [ 'B', '+', '1', 'Z' ], [ 'B', '+', '2', 'X' ],
  [ 'B', '+', '2', 'Y' ], [ 'B', '+', '2', 'Z' ],
  [ 'B', '-', '1', 'X' ], [ 'B', '-', '1', 'Y' ],
  [ 'B', '-', '1', 'Z' ], [ 'B', '-', '2', 'X' ],
  [ 'B', '-', '2', 'Y' ], [ 'B', '-', '2', 'Z' ] 
]