Java String.join 和制表符

我正在try 使用分隔符拆分字符串，对元素执行操作，然后使用相同的分隔符再次连接在一起.

String[] split = input.split(deli); // split on the string
// Do stuff with split
return String.join(delimiter,split); // join with the same string

This works fine, unless the used deli is '\t' (tab) (and probably other similar ones).
Because String.join refers to the delimiter as a 'charsequence' might this be the cause?

例如:

 var deli="\t";
 var split = data.split(deli); // splits properly
 var join = String.join(deli,split); // joins with sequence instead of char 
 var it = join.split(deli); // doesn't work

Is this normal? If so, how can I best work around it?
For now i'm doing this.

var deli="\t";
var split = data.split(deli); // splits properly
if( deli.equalsIgnoreCase("\\t")) 
     return String.join(String.valueOf((char)9),items);
return String.join(deli,items);

分隔符是从一个XML文件属性读取的，它被读取为"\\t"，而不是"\t"(在ide调试中，它显示为\t).这是意料之中的，但因为分手总是奏效，所以从来没有想过这一点.

// First split works, second doesn't
    var input ="[2023-04-25 07:31:26.175]\t1\tgeneric:qsr2150|par\t1770.112, 10.25, 9.043";
    var deli = "\\t";
    String[] split = input.split(deli); // splits properly
    var join = String.join(deli,split);
    var split2 = join.split(deli); // doesn't split

// Both splits work
    var input ="[2023-04-25 07:31:26.175]\t1\tgeneric:qsr2150|par\t1770.112, 10.25, 9.043";
    var deli = "\t";
    String[] split = input.split(deli);
    var join = String.join(deli,split);
    var split2 = join.split(deli); // splits properly

所以我的问题的解决方案是将属性正确地转换为‘制表符’.

但是，为什么第一个分拆可行，而第二个分拆行不通？你本以为第一次分手就会失败.