.com/r/IohlS8/1" rel="nofollow noreferrer">this是我的正则表达式，我正在try 使用此正则表达式查找双引号内字符串"VARIANT"的所有匹配项，但如果双引号内有2个匹配项，则只接受最后一个.我的正则表达式基本上是试图找到写在双引号中的字符串"VARIANT"，我试着这样写，但也不起作用:\\".*(variant*).*\\"这是我的代码:
String str_regex = "\\".*(variant).*\\"";
Matcher str_matcher = Pattern.compile(str_regex).matcher(joined);
while(str_matcher.find()) {
System.out.println(str_matcher.group());
}
您可以匹配双引号内字符串的所有匹配项，然后计算匹配项中的variant个匹配项:
String s = "variant \"if and only if 5 divides by i without remainder, then it prints \\\"i + \\\" variant: \\\" + variant\\\"\" variant";
Pattern pattern = Pattern.compile("(?s)(?<!\\\\)(?:\\\\{2})*\"[^\"\\\\]*(?:\\\\.[^\"\\\\]*)*\"");
Matcher matcher = pattern.matcher(s);
int count = 0;
while (matcher.find()){
count += matcher.group().split("variant", -1).length-1;
}
System.out.println(count);
请看online demo.因此，variant "if and only if 5 divides by i without remainder, then it prints \"i + \" variant: \" + variant\"" variant字符串包含两个variant匹配项.
正则表达式是(?<!\\)(?:\\{2})*"[^"\\]*(?:\\.[^"\\]*)*"，请参见.com/r/IohlS8/2" rel="nofollow noreferrer">its demo.
Details:
(?<!\\)--不允许\紧靠左侧(?:\\{2})*-零个或多个双反斜杠"-"个字符[^"\\]*-"和\以外的零个或更多字符(?:\\.[^"\\]*)*-任何转义字符的零个或多个序列，然后是\和"以外的零个或多个字符"-"个字符.