Ios 如何解码没有名称的 JSON 数组

问题出在您的JSONDecoder日期DecodingStrategy中.默认策略称为deferredToDate，这意味着它期待timeIntervalSinceReferenceDate.您需要一个定制的日期格式来解析您的ISO8601日期格式.判断一下这个How to convert a date string with optional fractional seconds using Codable in Swift?.

只需创建一个包含和不包含小数秒的自定义DateForMatter is8601:

extension Formatter {
    static let iso8601withFractionalSeconds: DateFormatter = {
        let formatter = DateFormatter()
        formatter.calendar = Calendar(identifier: .iso8601)
        formatter.locale = Locale(identifier: "en_US_POSIX")
        formatter.timeZone = TimeZone(secondsFromGMT: 0)
        formatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss.SSS"
        return formatter
    }()
    static let iso8601: DateFormatter = {
        let formatter = DateFormatter()
        formatter.calendar = Calendar(identifier: .iso8601)
        formatter.locale = Locale(identifier: "en_US_POSIX")
        formatter.timeZone = TimeZone(secondsFromGMT: 0)
        formatter.dateFormat = "yyyy-MM-dd'T'HH:mm:ss"
        return formatter
    }()
}

和一个自定义的日期解码策略:

extension JSONDecoder.DateDecodingStrategy {
    static let customISO8601 = custom {
        let container = try $0.singleValueContainer()
        let string = try container.decode(String.self)
        if let date = Formatter.iso8601withFractionalSeconds.date(from: string) ?? Formatter.iso8601.date(from: string) {
            return date
        }
        throw DecodingError.dataCorruptedError(in: container, debugDescription: "Invalid date: \(string)")
    }
}

现在，您可以正确设置JSONDecoder日期DecodingStrategy:

let decoder = JSONDecoder()
decoder.dateDecodingStrategy = .customISO8601

并使用该解码器解析您的JSON字符串.请注意，如果您使用Try？您正在丢弃应该用来调试问题的错误:

    return try decoder.decode([User].self, from: json) 
} catch {
    print(error)
}