我想创建全局错误处理程序,通过邮箱发送.
package main
import (
"github.com/gorilla/mux"
"log"
"net/http"
)
func main() {
rtr := mux.NewRouter()
rtr.HandleFunc("/", withPanic).Methods("GET")
http.Handle("/", rtr)
log.Println("Listening...")
http.ListenAndServe(":3001", http.DefaultServeMux)
}
func withPanic(w http.ResponseWriter, r *http.Request) {
panic("somewhere here will be panic, but I don't know where exactly")
}
如何使其全球化.如果我知道错误会发生在哪里,那就很容易了
if err != nil {
sendMeMail(err)
}
但是,当我不知道错误将在哪里发生时,该怎么办呢?所以我应该添加一个全局recover
左右的处理程序.但具体怎么做我不知道.
Update
我将defer recover
加到main
的开头,但它从未在请求http://localhost:3001
时执行.所以panic 不会通过邮箱发送.
package main
import (
"errors"
"fmt"
"github.com/gorilla/mux"
"log"
"net/http"
)
func main() {
defer func() {
if r := recover(); r != nil {
fmt.Println("Recovered in f", r)
// find out exactly what the error was and set err
var err error
switch x := r.(type) {
case string:
err = errors.New(x)
case error:
err = x
default:
err = errors.New("Unknown panic")
}
if err != nil {
// sendMeMail(err)
fmt.Println("sendMeMail")
}
}
}()
rtr := mux.NewRouter()
rtr.HandleFunc("/", withPanic).Methods("GET")
http.Handle("/", rtr)
log.Println("Listening...")
http.ListenAndServe(":3001", http.DefaultServeMux)
}
func withPanic(w http.ResponseWriter, r *http.Request) {
panic("somewhere here will be panic, but I don't know where exactly")
}