Csharp 如何实现一个通用的c#接口

发布于08月11日

我很难理解我的问题在这里是什么. CS0452 error, The type T must be ref type in order to use as a parameter...个

错误在此行上: Response<T> tableEntity = TC.GetEntity<T>(pk, rk);个

using Azure;
using Azure.Data.Tables;

namespace AzureDataTables
{
    public class AzureDataTables<T> : IAzureDataTables<T> where T : class, ITableEntity, new()
    {
        ITableEntity GetTableEntity(string pk, string rk);
    }

    public class AzureDataTables<T> : IAzureDataTables<T> where T : ITableEntity, new()
    {
        public T GetTableEntity(string pk, string rk)
        {
            var tableEntity = TC.GetEntity<T>(pk, rk);
            return tableEntity.Value;
        }
        public TableServiceClient TSC { get; set; } = new TableServiceClient("");
        public TableClient TC => TSC.GetTableClient("");
    }
}

推荐答案

如果接口的协定中有泛型类型，则需要在接口的实现中使用具体类型.下面是一个实用的示例:

using Azure;
using Azure.Data.Tables;

namespace AzureDataTables
{
    public interface IAzureDataTables<T> where T : class, ITableEntity, new()
    {
        ITableEntity GetTableEntity(string pk, string rk);
    }

    public class AzureDataTables<T> : IAzureDataTables<T> where T : class, ITableEntity, new()
    {
        public ITableEntity GetTableEntity(string pk, string rk)
        {
            Response<T> tableEntity = TC.GetEntity<T>(pk, rk);
            return tableEntity.Value;
        }

        public TableServiceClient TSC { get; set; } = new TableServiceClient("");
        public TableClient TC => TSC.GetTableClient("");
    }
}