我想使用FOR XML将此输出复制为从数据库到XML的可伸缩查询
<root>
<Gear id='1'>
<materials>
<material>
<id>2</id>
<material_name> Leather </material_name>
</material>
<material>
<id>1</id>
<material_name> Bar</material_name>
</material>
</materials>
<category>
<id>1</id>
<name>Warriors Weapon</name>
</category>
<equipment>
<id> 1</id>
<equipment_name> Claymore </equipment_name>
<category> 1</category>
</equipment>
<recipes>
<recipe>
<equipment_id>1</equipment_id>
<material_id>1</material_id>
<material_quantity>12</material_quantity>
</recipe>
<recipe>
<equipment_id> 1 </equipment_id>
<material_id>2</material_id>
<material_quantity>20</material_quantity>
</recipe>
</recipes>
</Gear>
<Gear id='2'>
<materials>
<material>
<id>3</id>
<material_name> Plank </material_name>
</material>
</materials>
<category>
<id>2</id>
<name>Hunter Weapons</name>
</category>
<equipment>
<id> 2</id>
<equipment_name> Bow </equipment_name>
<category> 2</category>
</equipment>
<recipes>
<recipe>
<equipment_id> 2 </equipment_id>
<material_id>3</material_id>
<material_quantity>36</material_quantity>
</recipe>
</recipes>
</Gear>
<Gear id='3'>
<materials>
<material>
<id>1</id>
<material_name> Bar </material_name>
</material>
</materials>
<category>
<id>4</id>
<name>Warrior Armour</name>
</category>
<equipment>
<id> 4</id>
<equipment_name> Knight Amor </equipment_name>
<category> 4</category>
</equipment>
<recipes>
<recipe>
<equipment_id> 4 </equipment_id>
<material_id>1</material_id>
<material_quantity>16</material_quantity>
</recipe>
</recipes>
</Gear>
</root>
这是我的实际数据库:
-- DDL and sample data population, start
USE tempdb;
GO
DROP TABLE IF EXISTS [dbo].[Categories];
DROP TABLE IF EXISTS [dbo].[Equipment];
DROP TABLE IF EXISTS [dbo].[Materials];
DROP TABLE IF EXISTS [dbo].[Recipe];
CREATE TABLE [dbo].[Categories](
[id] [int] NULL,
[name] [nvarchar](150) NULL
);
CREATE TABLE [dbo].[Equipment](
[id] [int] NULL,
[equipment_name] [nvarchar](50) NULL,
[category_id] [int] NULL
);
CREATE TABLE [dbo].[Materials](
[id] [int] NULL,
[material_name] [nvarchar](50) NULL
);
CREATE TABLE [dbo].[Recipe](
[equipment_id] [int] NULL,
[material_id] [int] NULL,
[material_quantity] [int] NULL
);
INSERT [dbo].[Categories] ([id], [name]) VALUES
(1, N'Warrior Weapons'),
(2, N'Hunter Weapons'),
(3, N'Mage Weapons'),
(4, N'Warrior Armours');
INSERT [dbo].[Equipment] ([id], [equipment_name], [category_id]) VALUES
(1, N'Claymore', 1),
(2, N'Bow', 2),
(3, N'Fire Staff', 3),
(4, N'Knight Armor', 4);
INSERT [dbo].[Materials] ([id], [material_name]) VALUES
(1, N'Bar'),
(2, N'Leather'),
(3, N'Plank'),
(4, N'Cloth');
INSERT [dbo].[Recipe] ([equipment_id], [material_id], [material_quantity]) VALUES
(1, 1, 20),
(1, 2, 12),
(2, 3, 32),
(3, 3, 16),
(3, 1, 8),
(4, 1, 16);
-- DDL and sample data population, end
因此,正如您所看到的,它就像一个名为Gear的类,包含一个material 数组、一个类别对象、一个设备对象和一个配方array.
如果添加了守护者护甲的新配方,我希望查询将其复制为具有上述 struct 的装备实例.
这样地:
<root>
[...]
<Gear id='4'>
<materials>
<material>
<id>1</id>
<material_name> Bar </material_name>
</material>
</materials>
<category>
<id>4</id>
<name>Warrior Armour</name>
</category>
<equipment>
<id> 5</id>
<equipment_name> Guardian Amor </equipment_name>
<category> 4</category>
</equipment>
<recipes>
<recipe>
<equipment_id> 5 </equipment_id>
<material_id>1</material_id>
<material_quantity>16</material_quantity>
</recipe>
</recipes>
</Gear>
</root>
gear ID只是一个参考,所以我认为附加到真实属性(如category\u ID)并不重要.