C++ C传递整个 struct 变量

这是一个 struct 简单的C程序，但我不太明白我做错了什么，因为输出不是我想要的，

P1个

#include<stdio.h>
struct book
{
    char name[10];
    char author[10];
    int refno;
};
//passing whole structure variable 
void display(struct book b)
{
    printf("%s %s %d",b.name,b.author,b.refno);
}
int main()
{
    
    struct book b1={"LET US C","YPK",25};
    display(b1);
}

在这里，这个命令可以很好地处理输出:

LET US C YPK 25
--------------------------------
Process exited after 0.3952 seconds with return value 0
Press any key to continue . . .

如果我试一试，会有BUT

struct{
// element -1;
//element -2;
//element-3;
}b1;

/*then*/
int main()
{
 b1={"LET US C","YPK",25};
display(b1);

它显示错误消息:-

1:[Warning] extended initializer lists only available with -std=c++11 or -std=gnu++11
2:[Error] no match for 'operator=' (operand types are 'book' and '<brace-enclosed initializer list>')
3:[Note] candidate is:
4:[Note] book& book::operator=(const book&)
5:[Note] no known conversion for argument 1 from '<brace-enclosed initializer list>' to 'const book&'

如果我try 执行以下操作，将显示相同的消息:

struct book 
{
//elements declarations as p1
}b[10];

int main()
{
b[1]={"LET US C","YPK",25};
display(b[1]);
}

OR WITH个

struct book
{
//elements declarations as p1
};
int main()
{
    struct book b[10];
    b[1]={"LET US C","YPK",25};
    display(b[1]);
}

那么问题出在哪里呢？

实际上，我的主要目标是定义 struct 数组，如倒数第二和倒数第二部分所示 方法，但它似乎不起作用，所以请帮助&gt；