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Object.getPrototypeOf()函数详解

JavaScript的 Object.getPrototypeOf()方法返回指定对象的原型(即内部[[Prototype]]属性的值)。

语法

Object.getPrototypeOf(obj)

参数

obj :这是要返回其原型的对象。

返回值

此方法返回给定对象的原型。如果没有继承的属性，则此方法将返回null。

浏览器支持

Chrome	5
Edge	yes
Firefox	3.5
Opera	12.1

例子1

复制代码

let animal = {
  eats: true
};
  //create a new object with animal as a prototype
let rabbit = Object.create(animal);
alert(Object.getPrototypeOf(rabbit) === animal);//get the prototype of rabbit

Object.setPrototypeOf(rabbit, {});//change the prototype of rabbit to {}

输出:

true

例子2

复制代码

const prototype1 = {};
const object1 = Object.create(prototype1);
const prototype2 = {};
const object2 = Object.create(prototype2);
console.log(Object.getPrototypeOf(object1) === prototype1);
console.log(Object.getPrototypeOf(object1) === prototype2);

输出:

true
false

例子3

复制代码

const prototype1 = {};
const object1 = Object.create(prototype1);
const prototype2 = {};
const object2 = Object.create(prototype2);
console.log(Object.getPrototypeOf(object1) === prototype1);
console.log(Object.getPrototypeOf(object2) === prototype2);