在python中计算平均值

发布于06月23日

I've made this console application and it works...but only when you enter small numbers in the input like 1 in 'ifrom', 2 in 'step', and 3 in 'to'...but when I enter bigger numbers in 'to' for example 100 it just do nothing!!! It even doesn't give me any error! Thanks!

print("---Average2---"+"\n")

sum=0
average=0
counter=0

while True:
    ifrom=int(input("From: "))
    step=int(input("Step: "))
    to=int(input("To: "))
    while sum<=to:
        sum=ifrom+step
        counter+=1
        if sum==to:
            print("\n"+"The sum is: ",sum)
            average=sum/counter
            print("The average is: ",average,"\n")
            sum=0
            average=0
            counter=0
            break

推荐答案

There are two reasons of this behavior

You're adding constantly sum = ifrom + step which is a constant value (in your example: 1 + 2 = 3). So in every loop iteration your sum will be 3 and will never hit 100
Even if you fix the first problem, your example sum variable is going to be 1, 3, 5, ..., 99, 101, .... You're checking if the sum is 100 and the program is doing nothing, because it will bever hit 100.

Possible solutions:

use range syntax (recommended - you can use this solution )
check if the variable reached 100 (instead of checking if it is equal 100) like below:

print("---Average2---"+"\n")

average=0
counter=0
tmp=0

while True:
   ifrom=int(input("From: "))
   step=int(input("Step: "))
   to=int(input("To: "))
   tmp = ifrom
   sum = tmp
   while tmp<=to:
       tmp+=step
       sum+=tmp
       counter+=1
       if tmp>=to:
           if tmp>to:
             sum-=tmp
           print("\n"+"The sum is: ",sum)
           average=sum/counter
           print("The average is: ",average,"\n")
           sum=0
           average=0
           counter=0
           break