dot product of lists python
import numpy as np # input: [[1,2,3,...], [4,5,6,...], ...] def dot_product(vector, print_time= True): if print_time: print("----Dot Product----") dot_product = [] for j in range(len(vector[0])): col = [] for i in range(len(vector)): col.append(vector[i][j]) prod_col = np.prod(col) dot_product.append(prod_col) sum_dot_product = np.sum(dot_product) if print_time: print(f"input vector: {vector}, => dot product = {sum_dot_product}") print("================================") return sum_dot_product vector1 = [1,2,3] vector2 = [4,5,6] vector3 = [2,4,3] vector4 = [2,4,3] vector = [vector1, vector2, vector3, vector4] dot_product(vector) # or dot_product([vector2, vector4]) # or # the False parameter, disables the printing in the function. print(dot_product(vector,False))
dot product python
A = [1,2,3,4,5,6] B = [2,2,2,2,2,2] # with numpy import numpy as np np.dot(A,B) # 42 np.sum(np.multiply(A,B)) # 42 #Python 3.5 has an explicit operator @ for the dot product np.array(A)@np.array(B)# 42 # without numpy sum([A[i]*B[i] for i in range(len(B))]) # 42
Source: stackoverflow.com