python dictionary
#Creating dictionaries dict1 = {'color': 'blue', 'shape': 'square', 'volume':40} dict2 = {'color': 'red', 'edges': 4, 'perimeter':15} #Creating new pairs and updating old ones dict1['area'] = 25 #{'color': 'blue', 'shape': 'square', 'volume': 40, 'area': 25} dict2['perimeter'] = 20 #{'color': 'red', 'edges': 4, 'perimeter': 20} #Accessing values through keys print(dict1['shape']) #You can also use get, which doesn't cause an exception when the key is not found dict1.get('false_key') #returns None dict1.get('false_key', "key not found") #returns the custom message that you wrote #Deleting pairs dict1.pop('volume') #Merging two dictionaries dict1.update(dict2) #if a key exists in both, it takes the value of the second dict dict1 #{'color': 'red', 'shape': 'square', 'area': 25, 'edges': 4, 'perimeter': 20} #Getting only the values, keys or both (can be used in loops) dict1.values() #dict_values(['red', 'square', 25, 4, 20]) dict1.keys() #dict_keys(['color', 'shape', 'area', 'edges', 'perimeter']) dict1.items() #dict_items([('color', 'red'), ('shape', 'square'), ('area', 25), ('edges', 4), ('perimeter', 20)])
how to use dictionaries in python
student_data = { "name":"inderpaal", "age":21, "course":['Bsc', 'Computer Science'] } #the keys are the left hand side and the values are the right hand side #to print data you do print(name_of_dictionary['key_name']) print(student_data['name']) # will print 'inderpaal' print(student_data['age']) # will print 21 print(student_data['course'])[0] #this will print 'Bsc' since that field is an array and array[0] is 'Bsc'
python dictionary
#title :Dictionary Example #author :Josh Cogburn #date :20191127 #github :https://github.com/josh-cogburn #==================================================== thisdict = { "brand": "Ford", "model": "Mustang", "year": 1964 } #Assigning a value thisdict["year"] = 2018
dictionary python
# dictionary refresh new_dict = { "first":"1,2,3", "second":"321", "third":"000", } # adding to dictionary new_dict.update({"fourth":"D"}) print(new_dict) #removing from dictionary new_dict.pop("first") print(new_dict) new = {"five":"888"} #updating a dictionary new_dict.update(new) print(new_dict)
python dictionary
<view> = <dict>.keys() # Coll. of keys that reflects changes. <view> = <dict>.values() # Coll. of values that reflects changes. <view> = <dict>.items() # Coll. of key-value tuples that reflects chgs. value = <dict>.get(key, default=None) # Returns default if key is missing. value = <dict>.setdefault(key, default=None) # Returns and writes default if key is missing. <dict> = collections.defaultdict(<type>) # Creates a dict with default value of type. <dict> = collections.defaultdict(lambda: 1) # Creates a dict with default value 1. <dict> = dict(<collection>) # Creates a dict from coll. of key-value pairs. <dict> = dict(zip(keys, values)) # Creates a dict from two collections. <dict> = dict.fromkeys(keys [, value]) # Creates a dict from collection of keys. <dict>.update(<dict>) # Adds items. Replaces ones with matching keys. value = <dict>.pop(key) # Removes item or raises KeyError. {k for k, v in <dict>.items() if v == value} # Returns set of keys that point to the value. {k: v for k, v in <dict>.items() if k in keys} # Returns a dictionary, filtered by keys.
Source: gto76.github.io
python dictionary
l = {"a":"aaaaa"} print(l["a"]) #aaaa l = [{"a":"aaaaa"}, {"a":"AAA65675765"}] print(l[0]["a"]) #aaaa
python dictionary
human = { "code": "Python", "name": "John", "age": 32 } print(human["age"]) #32 :D
dicts python
thisdict = { "brand": "Ford", "model": "Mustang", "year": 1964 } x = thisdict["model"] print(x) --------------------------------------------------------------------------- Mustang
dictionary python
dictionary = { "name": "Elie", "family name": "Carcassonne", "date of born": "01/01/2001", "list": ["hey", "hey"] }
Source: openclassrooms.com
python dictionary
# Creating an empty Dictionary Dict = {} print("Empty Dictionary: ") print(Dict) # Creating a Dictionary # with dict() method Dict = dict({1: 'Geeks', 2: 'For', 3:'Geeks'}) print("\nDictionary with the use of dict(): ") print(Dict) # Creating a Dictionary # with each item as a Pair Dict = dict([(1, 'Geeks'), (2, 'For')]) print("\nDictionary with each item as a pair: ") print(Dict)
Source: www.geeksforgeeks.org
python dictionary
txt = "this is a wild string" print(txt.replace("i", "x")) # print string with all i characters replaced with x print(txt.replace("i", "x", 2)) # print string with first two i characters found with x print(txt.upper()) # print string in all uppercase letters print(txt.lower()) # print string in all uppercase letters print(ord('A')) # print the ordinal value of a character print(chr(95)) # print character from its ordinal value print('Yes' * 5) # print string Yes 5 times # Reference strings by index print(txt[0]) # print first letter of string from starting index print(txt[0:2]) # print first two letters from starting index print(txt[1:]) # print all characters except the first letter print(txt[0::2]) # print every second character print(txt[::-1]) # print string in reverse print(txt[-1]) # print the last character in a string print(txt[-2:]) # print the last who characters in a string # check if a wild is found in txt if "wild" in txt: print("wild is found in txt") # check if a blah is not found in txt if "blah" not in txt: print("is not found in txt") # Check if txt starts with this if txt.startswith("this"): print("Starts with this") # check if txt ends with ing if txt.endswith("ing"): print("Ends with ing") # Split a string into a tuple when the delimiter is first encountered txt = 'random-data' data_split = txt.partition('-') print(data_split) # output ('random', '-', 'data') len(txt) # Return length of string # loop through each character in string for char in txt: print(char) # Display price with commas and 2 digit precision price = 9749000 display_price = f"My price {price:,.2f}" print(display_price) fruits = ['orange', 'apple', 'pear', 'banana', 'kiwi', 'apple', 'banana'] fruits.count('apple') # count number of apples found in list # output 2 fruits.count('tangerine') # count number of tangerines in list # output 0 fruits.index('banana') # find the first index of banana # output 3 fruits.index('banana', 4) # Find next banana starting a position 4 # output 6 fruits.reverse() # reverse fruits array fruits # output ['banana', 'apple', 'kiwi', 'banana', 'pear', 'apple', 'orange'] fruits.append('grape') # append grape at the end of array fruits # output ['banana', 'apple', 'kiwi', 'banana', 'pear', 'apple', 'orange', 'grape'] fruits.sort() fruits # output ['apple', 'apple', 'banana', 'banana', 'grape', 'kiwi', 'orange', 'pear'] len(fruits) # length of fruits array # output 8 # loop and print each fruit for fruit in fruits: print(fruit) empty_set = set() basket = {'apple', 'orange', 'apple', 'pear', 'orange', 'banana'} print(basket) # show that duplicates have been removed # output {'orange', 'banana', 'pear', 'apple'} # check if orange is in basket set print('orange' in basket) # output true # convert a string to a set of letters - sets contains no duplicates set_a = set('abcd') set_b = set('bcde') # the operations below returns new sets # print letters in set_a but not in set_b - difference print(set_a - set_b) # output {'a'} # print set letters that is in either set a or b - union print(set_a | set_b) # output {'a', 'c', 'e', 'b', 'd'} # print letters that are in both set_a and set_b - intersection print(set_a & set_b) # output {'c', 'd', 'b'} # print letters that are in set_a and set_b when the letters are found in a set but no the other set - symmetric_difference() print(set_a ^ set_b) # output {'a', 'e'} # Creating dictionaries dict1 = {'color': 'blue', 'shape': 'square', 'volume': 40} dict2 = {'color': 'red', 'edges': 4, 'perimeter': 15} # Creating new pairs and updating old ones dict1['area'] = 25 # {'color': 'blue', 'shape': 'square', 'volume': 40, 'area': 25} dict2['perimeter'] = 20 # {'color': 'red', 'edges': 4, 'perimeter': 20} # Accessing values through keys - an KeyError will occur if the key does not exists print(dict1['shape']) # You can also use get, which doesn't cause an exception when the key is not found dict1.get('false_key') # returns None dict1.get('false_key', "key not found") # returns the custom message that you wrote # Delete item key and return the value if the key does not exists a KeyError occurs print(dict1.pop('volume')) # Merging two dictionaries dict1.update(dict2) # if a key exists in both, it takes the value of the second dict dict1 # {'color': 'red', 'shape': 'square', 'area': 25, 'edges': 4, 'perimeter': 20} # Getting only the values, keys or both (can be used in loops) dict1.values() # dict_values(['red', 'square', 25, 4, 20]) dict1.keys() # dict_keys(['color', 'shape', 'area', 'edges', 'perimeter']) dict1.items() # dict_items([('color', 'red'), ('shape', 'square'), ('area', 25), ('edges', 4), ('perimeter', 20)]) # create a shallow copy of dict1 dict3 = dict1.copy() # dict3 = {'color': 'red', 'shape': 'square', 'area': 25, 'edges': 4, 'perimeter': 20}
Source: codefreelance.net
dict python
a = {'a': 123, 'b': 'test'}
python dict
mydictionary = {'name':'python', 'category':'programming', 'topic':'examples'} for x in mydictionary: print(x, ':', mydictionary[x])
Source: www.howtouselinux.com
python dict
# A dict (dictionary) is a data type that store keys/values myDict = {"name" : "bob", "language" : "python"} print(myDict["name"]) # Dictionaries can also be multi-line otherDict { "name" : "bob", "phone" : "999-999-999-9999" }
python Dictionaries
#Python dictionaries consists of key value pairs tha #The following is an example of dictionary state_capitals = { 'Arkansas': 'Little Rock', 'Colorado': 'Denver', 'California': 'Sacramento', 'Georgia': 'Atlanta' } #Adding items to dictionary #Modification of the dictionary can be done in similar maner state_capitals['Kampala'] = 'Uganda' #Kampala is the key and Uganda is the value #Interating over a python dictionary for k in state_capitals.keys(): print('{} is the capital of {}'.format(state_capitals[k], k))
python dictionary
dict_name = {"key1": "value1", "key2": "value2", ...}
python dictionary
stationary_items = { "Pencil":"Pencil is used to write things in copy", "Eraser": "Eraser is used to remove the written things", "Sharpner":"This is used to sharp your pencil" } print(stationary_items["Pencil"])
Python Dictionaries
thisdict = { "brand": "Ford", "model": "Mustang", "year": 1964 } print(thisdict["brand"])
python dict
>>> d = {} >>> d {} >>> d = {'dict': 1, 'dictionary': 2} >>> d {'dict': 1, 'dictionary': 2}
Source: pythonworld.ru
python dictionary
alien = {'color': 'green', 'points': 5}
Source: nostarch.com
python dictionary
# Create the "car" dictionary car = { "make": "abc", "model": "def", "top_speed": 150, } # Print the top speed print(car["top_speed"]) # Change the make car["make"] = "ghi"
python dictionary
#Creating dictionaries dict1 = {'color': 'blue', 'shape': 'square', 'volume':40} dict2 = {'color': 'red', 'edges': 4, 'perimeter':15}
dictionaries in python
# Creating a Nested Dictionary # as shown in the below image Dict = {1: 'Geeks', 2: 'For', 3:{'A' : 'Welcome', 'B' : 'To', 'C' : 'Geeks'}} print(Dict)
Source: www.geeksforgeeks.org
python dictionaries
>>> tel = {'jack': 4098, 'sape': 4139} >>> tel['guido'] = 4127 >>> tel {'jack': 4098, 'sape': 4139, 'guido': 4127} >>> tel['jack'] 4098 >>> del tel['sape'] >>> tel['irv'] = 4127 >>> tel {'jack': 4098, 'guido': 4127, 'irv': 4127} >>> list(tel) ['jack', 'guido', 'irv'] >>> sorted(tel) ['guido', 'irv', 'jack'] >>> 'guido' in tel True >>> 'jack' not in tel False
Source: docs.python.org